Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
D because a rational number can be converted into a fraction and the square root of 5 cannot be covert into a fraction because it equals 2.2
Based on the stated annual interest rate and the face value of the bond, the semiannual payments will be $1,000,000.
<h3>How can the semiannual interest payment be found?</h3>
The formula to find the semiannual payment is:
= (Face value x Stated annual interest rate) / 2 semi-annual periods per year
Solving gives:
= (50,000,000 x 4%) / 2
= 2,000,000 / 2
= $1,000,000
Find out more on bond payments at brainly.com/question/22488444.
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Answer:
7 teams remaining a person
Step-by-step explanation:
29/4 = 7 remainder 1
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