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sertanlavr [38]
3 years ago
9

PLEASE HELP!!! WILL MARK BRAINIEST!!!

Mathematics
1 answer:
Delvig [45]3 years ago
4 0

m∠CBD = m∠BFE Given

m∠CBD + m∠DBF = 180° Supplementary Angles

m∠BFE + m∠DBF = 180° Supplementary Angles

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M is between L and N. LM = 7x-1, MN = 2x +4, and LN = 12. find the value of ‘x’ an determine if M is a bisector.
Sholpan [36]

LM + MN = LN

7x - 1 + 2x + 4 = 12

9x + 3 = 12

9x = 12 - 3

9x = 9

x = 9/9

x = 1

7 0
3 years ago
Two semicircles are attached to the sides of a rectangle as shown.
melomori [17]

Answer:

157\ in^{2}

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of two semicircles

<u>The area of rectangle is equal to</u>

A=14*5=70\ in^{2}

<u>The area of the small semicircle is equal to</u>

A=\pi r^{2} /2

r=5/2=2.5\ in -----> radius is half the diameter

substitute

A=(3.14)(2.5^{2})/2=9.8125 in^{2}

<u>The area of the larger semicircle is equal to</u>

A=\pi r^{2} /2

r=14/2=7\ in -----> radius is half the diameter

substitute

A=(3.14)(7^{2})/2=76.93\ in^{2}

The area of the figure is equal to

70+9.8125+76.93=156.7425=157\ in^{2}

8 0
3 years ago
Read 2 more answers
HELP ASAP Use the data below
beks73 [17]

Answer:

Part A:

   -Minimum: 10

   -Q1: 17.5

   -Median: 30

   -Q3: 42.5

   -Maximum: 50

Step-by-step explanation:

Part B: IQR= 25

This shows that the data varies for 25 different numbers. That HALF of the data is between 25 numbers.

Part C: Using a box-and-whisker plot you can interpret the different values. Minimum is the first dot (10), connected to the first line (Q1 which is 17.5), connected by a box to the median (30), connected by a box to the third line (Q3 which is 42.5), connected to the last dot which is the maximum (50). And IQR is Q3-Q1, so 42.5-17.5 which is 25.

8 0
4 years ago
A photo is 15 cm high and 9 cm wide Michael wants to but porcelain shrink it so it's height is 6 cm High how wide will it then b
weqwewe [10]

Answer:

3.6cm

Step-by-step explanation:

Given data

We are given that the dimension of the photo is

Height= 15cm

Width= 9cm

That is

            15cm height  will make 9cm width

hence    6cm height will make x widht

cross multiply

9*6= 15*x

54= 15x

x= 54/15

x= 3.6cm

Hence the width will be 3.6cm

3 0
3 years ago
I’m boredddd
Roman55 [17]

Answer:

hi

Step-by-step explanation:

how r u today im amaxing

8 0
3 years ago
Read 2 more answers
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