Please read the photo above first :))a) 40b) 160 c) 240d) 320
1 answer:
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Answer:
Step-by-step explanation:
-2x + 2y = -4 (times 3) -6x + 6y = -12
3x + 3y = -18 (times 2) 6x + 6y = -36
.
-6x + 6y = -12
<u>6x + 6y = -36 </u>+
12y = -48
y = -4
.
Substitute the value of y to the one of equations
-2x + 2(-4) = -4
-2x - 8 = -4
-2x = -4 + 8
-2x = 4
x = -2
Given:
Line a passes through (2, 10) and (4, 13).
Line b passes through (4, 9) and (6, 12).
Line c passes through (2, 10) and (4, 9).
To find:
Which of the lines, if any are perpendicular.
Solution:
If a line passes through two points, then the slope of line is
Line a passes through (2, 10) and (4, 13). So, slope of this line is
Line b passes through (4, 9) and (6, 12). So, slope of this line is
Line c passes through (2, 10) and (4,9). So, slope of this line is
Product of slopes of to perpendicular lines is -1.
Therefore, any of these lines are not perpendicular to each other.