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RSB [31]
3 years ago
15

Write 310s and 600s as a percent

Mathematics
1 answer:
Assoli18 [71]3 years ago
6 0
310 as a percent is equal to 30%
600 as a percent is equal to 6%
You might be interested in
Simplify the expression 3x•(7•x) explain
yuradex [85]

Steps to solve:

3x * (7 * x)

~Simplify

3x * 7x

~Combine like terms

21x

Best of Luck!

7 0
2 years ago
Read 2 more answers
Which of the following will generate a graph that is 3 units to the left of y = x3?
Mamont248 [21]

Answer:

(3) y=(x+3)

Step-by-step explanation:

I'm not sure what is the parent function, but in most graphs if you will shift it to the left or right (negative sign or positive sign, respectively), it will be inside a parenthesis and the opposite sign is the real movement.

For a cubic function these will be the movements:

f(x)=(x+/-h)^3+/-k

Only the opposite sign of h will be the real movement, while k's sign will automatically indicate the correct movement.

h= x-axis movement (horizontal, inside of the parenthesis in the equation)

k= y-axis movement (vertical, outside of the parenthesis in the equation)

Hope it helps

4 0
2 years ago
How much lighter is 345 g than 1,1 kg​
NemiM [27]

Answer:

755 gram lighter

Step-by-step explanation:

Convert 1.1kg into gram by multiplying it with 1000

1.1 x 1000= 1100 and we take this amount and subtract it with 345g

1100-345= 755g

3 0
3 years ago
Is square root of 7 a rational number
MAVERICK [17]

Answer: Yeah its a rational number.

5 0
2 years ago
Consider the given matrix. 1 −1 0 5 1 4 0 1 1 Find the eigenvalues. (Enter your answers as a comma-separated list.) λ = Find the
fomenos

Answer:

Step-by-step explanation:

We have to diagonalize the matrix

\left[\begin{array}{ccc}1&-1&0\\5&1&4\\0&1&1\end{array}\right]

we have to solve the expression

|A-\lambda I|=0

Thus, by applying the determinant we obtain the polynomial

(1-\lambda )^3+5-4=0\\(1-\lambda )^3+1=0\\

-\lambda^3+3\lambda^2-4\lambda+2

\lambda_1=1\\\lambda_2=1-i\\\lambda_3=1+i\\

and the eigenvector will be

v_1=(-4,0,5)\\v_2=(-1,-i,-1)\\v_3=(-1,i,1)

HOPE THIS HELPS!!

3 0
3 years ago
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