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aksik [14]
3 years ago
12

A package of 5 pairs of insulated socks costs $36.95. What is the unit price of the pairs of socks

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
3 0

Hey there! :)

Answer:

$7.39 per pair of socks.

Step-by-step explanation:

Find the price per pair of socks by dividing the total price by the number of socks:

36.95 ÷ 5 = $7.39 per pair of socks.

puteri [66]3 years ago
3 0

Answer:

Step-by-step explanation:

cost of 5 pairs of socks = $36.95

∴ Cost of 1 pair of socks = 36.95 ÷ 5

= $7.39

hope this helps

plz mark it as brainliest!!!!!!!

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Which of these expressions can be used to calculate the monthly payment for
Masja [62]

Answer:

m=(r/n)+0.114r

Step-by-step explanation:

m=monthly payment

r=remaining amount

n=# of months remaining

7 0
3 years ago
An airplane travel at a constant speed of 575 miles per hour.write and equation that can be used to determine the number of mile
Oxana [17]

Answer:

m = 575h

Step-by-step explanation:

Given

Rate = 575 miles/hour

Required

Determine the equation for the model

Represent the number of hours with h and the miles with m.

Using distance formula:

Distance = Speed * Time

In this case, it is:

Miles = Rate * Hour

So, we have:

m = 575 * h

m = 575h

3 0
2 years ago
Avery napped for 110 minutes. Natalie napped for 190 minutes.
galben [10]

Answer:

A.

Step-by-step explanation:

If Chrustina said that and if 110 and 70 don't add up to 190 then she is wrong

6 0
3 years ago
Read 2 more answers
The weight of 1000 identical samples of a substance is 1 pound. What is the weight of 100 samples?
alex41 [277]
The answer is 0.1 lbs. Or 1/10 lbs.

Hope this helps!
8 0
3 years ago
Read 2 more answers
9. Determine how long it takes for 80% of the material to decay.
Vilka [71]

Using an exponential function, it is found that it takes 18.6 days for 80% of the material to decay.

The amount of a substance after t days is modeled by:

A(t) = A(0)e^{-kt}

In which:

  • k is the decay rate, as a decimal.
  • A(0) is the initial amount.

The half-life is of 8 days, hence A(8) = 0.5A(0), and this is used to find k.

A(t) = A(0)e^{-kt}

0.5A(0) = A(0)e^{-8k}

e^{-8k} = 0.5

\ln{e^{-8k}} = \ln{0.5}

-8k = \ln{0.5}

k = -\frac{\ln{0.5}}{8}

k = 0.08664339757

Hence:

A(t) = A(0)e^{-0.08664339757t}

The time it takes for 80% of the material to decay it t for which A(t) = 0.2A(0), hence:

0.2A(0) = A(0)e^{-0.08664339757t}

e^{-0.08664339757t} = 0.2

\ln{e^{-0.08664339757t}} = \ln{0.2}

-0.08664339757t = \ln{0.2}

t = -\frac{\ln{0.2}}{0.08664339757}

t = 18.6

It takes 18.6 days for 80% of the material to decay.

To learn more about exponential functions, you can take a look at brainly.com/question/24906920

5 0
3 years ago
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