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neonofarm [45]
4 years ago
5

Someone please help me with this question I need it ASAP

Mathematics
1 answer:
ZanzabumX [31]4 years ago
6 0

Your question has been heard loud and clear.

First one (x+2i)(x-2i) = x^2+4

Second one (x-2+2i)(x-2-2i) = x^2-4x+8

Third one (x+1+i)(x+1-i) = x^2+2x+2

Thank you

Edit: Sorry for taking 15 minutes I was calculating lol

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3 years ago
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Please help me find the solution!!!!
Umnica [9.8K]

Answer:

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4 years ago
12. Factor completely: 64x^3 + 729
Dafna1 [17]

Answer:

(4 x + 9) (16 x^2 - 36 x + 81)

Step-by-step explanation:

Factor the following:

64 x^3 + 729

64 x^3 + 729 = (4 x)^3 + 9^3:

(4 x)^3 + 9^3

Factor the sum of two cubes. (4 x)^3 + 9^3 = (4 x + 9) ((4 x)^2 - (4 x) 9 + 9^2):

(4 x + 9) ((4 x)^2 - 4 9 x + 9^2)

4×9 = 36:

(4 x + 9) ((4 x)^2 - 36 x + 9^2)

Multiply each exponent in 4 x by 2:

(4 x + 9) (4^2 x^2 - 36 x + 9^2)

4^2 = 16:

(4 x + 9) (16 x^2 - 36 x + 9^2)

9^2 = 81:

Answer: (4 x + 9) (16 x^2 - 36 x + 81)

5 0
4 years ago
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Step-by-step explanation:

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