<span>1) Find an equation of the plane. The plane that passes through the point (2, 3, 4) and contains the line x = 4t, y = 2 + t, z = 3 − t 2) Find an equation of the plane. The plane that passes through (6, 0, −3) and contains the line x = 2 − 4t, y = 1 + 5t, z = 2 + 2t 3) Find an equation of the plane. The plane that passes through the point (1, −1, 1) and contains the line with symmetric equations x = 2y = 5z 4) Find the point at which the line intersects the given plane. x = 2 − t, y = 1 + t, z = 3t; x − y + 5z = 14 5) Find the point at which the line intersects the given plane. x = 2 + 2t, y = 3t, z = 4 − 2t; x + 2y − z + 2 = 0 6) Find the point at which the line intersects the given plane. x = y − 2 = 2z; 2x − y + 2z = 2</span>
Answer:
The slope is 2
Step-by-step explanation:
The formula to find slope is y2-y1/x2-x1
Plug in the numbers and you get: 5-3/1-2
The result of that is -2/-1 which can be simplified to 2
I believe the correct answer from the choices listed above is option D. The points where the object is traveling at the greatest speed would be <span>between points A and B because that slope is the steepest. The slope of this graph indicates speed since it will have the units of distance per time. The steeper the line is , the greater the value of the slope which would mean faster speed.</span>
The answer to the question
