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HACTEHA [7]
3 years ago
7

6x+2=-8+3x+25 whats the answer to x?

Mathematics
2 answers:
MArishka [77]3 years ago
4 0
X=5
6x+2=-8+3x+25
all common multiples on both side and get
6x+2=3x+17
subtract 2 from both sides and get
6x=3x+15
subtract 3x from both sides to get
3x=15
and then finally divide both sides by three to leave you with
x=5

Nitella [24]3 years ago
3 0

Answer:

x = 5

Step-by-step explanation:

To find the value of x make sure to get it on one side

First subtract 3x from each side. This makes the equation now

3x + 2 = -8 + 25

Now see what 25 subtract by 8 is (17)

3x + 2 = 17

Next subtract 2 from both sides

3x = 15

Lastly, divide 15 by 3, making x equal 5

x = 5

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Please help i dont understand :(
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Step-by-step explanation:

since the width of the bottom square is 10, you split it between the triangles on top. You have to do this because 7 is not the whole width of the two triangles. So then the width of the triangles would be 12, 12 times 9 is 108, you'd have 216 total for both triangles and then the area of the square is 90, 90 plus 216 is 306.

6 0
3 years ago
Johan takes out a 20-year mortgage at 4% to buy a house. When he looks at investing in 20-year, fixed-rate Treasuries, which of
Vsevolod [243]
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6 0
3 years ago
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a building security code has 2 numeric digits 0 through 9 followed by 2 letters. what is the probability that the first digit is
sleet_krkn [62]

If we remove human choices in creating the code the answer is 10 (the possible choices) times 26 (the possible choices) so 260 is the probability

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4 years ago
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What is 9/136 in simplest form??
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Answer:

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Step-by-step explanation:

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3 years ago
A survey of households revealed that 38% have a dog, 47% have a cat, and 15% have both a cat and a dog.
coldgirl [10]

Answer:

I) P(cat│dog) = \frac{0.15}{0.38}

II) These events are not independent

III) P(cat or dog)=  0.7

Step-by-step explanation:

Given : Households have  dogs = 38%

           So, P(dog) = 0.38

           Households have  cats = 47%

           So, P(cats) = 0.47

             Households have both dogs and cats  = 15%

           So, P(both dog and cat ) = P(cat\cap dog) = 0.15

solution :

i) By formula P(A│B) =\frac{P(A\cap B)}{P(B)}

P(cat│dog)= \frac{P(cat\cap dog)}{P(dog)}

P(cat│dog) = \frac{0.15}{0.38}

ii)  P(cat│dog)=39.47% = 0.39 and P(cat)=47% = 0.47, are the events not independent

Because condition for independent events in conditional probability is P(A|B)=P(A)

but P(cat│dog) ≠P(cat) i.e. 0.39≠0.47

So, these events are not independent

iii) P(cat or dog) = ?

"or" means union

Formula : P(A\cup B)= P(A) + P(B)-P(A\cap B)

P(cat or dog) = P(cat\cup dog)= P(cat) + P(dog)-P(cat\cap dog)

P(cat or dog)= 0.47 + 0.38 - 0.15

P(cat or dog)=  0.7


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