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2 years ago

4x+5=x(x+8) how do I solve this?

Mathematics

1 answer:

GenaCL600 [577]2 years ago

3 0

Answer:

$x=1,-5$

Step-by-step explanation:

$We\ are\ given\ that,\\4x+5=x(x+8)\\Hence\ by\ expanding\ the\ terms,\\4x+5=x^2+8x\\Hence\ by\ moving\ 4x\ and\ 5 to\ the\ RHS\ ,\\0=x^2+8x-4x-5\\Hence\ by\ simplifying\ the\ RHS,\\0=x^2+4x-5\\Now,\\We\ take\ a\ closer\ look\ at\ the\ RHS,\\x^2+4x-5\ can\ also\ be\ written\ as:\\=x^2+5x-x-5\\Now, By\ factorizing,\\x(x+5)-1(x+5)\\=(x-1)(x+5)\\Hence,\\(x-1)(x+5)=0\\Now,\\To\ nullify\ the\ LHS\ to\ 0,\ either\ the\ term\ (x-1)\ or/and\ (x+5)\ should\ equate\ to\ 0.\\Hence,\\x-1=0\\$ $x=1\ is\ our\ first\ solution\\(x+5)=0\\x=-5\ is\ our\ second\ solution\\Hence,\\x=1,-5$

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At the end of a recent WNBA regular season, the Phoenix murmur had 12 more victories than losses. The number of victories they h

Hoochie [10]

Answer:

34 games

Step-by-step explanation:

let the number of losses be $l$

let the number of victories be $v$

the Phoenix murmur had 12 more victories than losses:

$v=l+12$

The number of victories they had was one more than two times the number of losses:

$v=2l+1$

We have 2 expressions for $v$ , equating these 2, we can solve for $l$ :

$l+12=2l+1\\12-1=2l-l\\11=l$

So 11 games, they lost.

Using this value, we can plug into the 1st equation to solve for v:

$v=l+12\\v=11+12\\v=23$

So 23 games, they won.

Given that no draws, they played a total of 23 + 11 = 34 games this season

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3 years ago

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2 years ago

X + 6 = −x − 6 (so i can ask)kjhgfdccfghjk

ratelena [41]

Answer:

x = -6

Step-by-step explanation:

Equations

Solve the equation:

x + 6 = -x - 6

We must find the value of x that makes the identity above true.

Let's join all the variables on the left side and the numbers on the right side.

Adding x:

x + 6 + x = -x - 6 + x

The variables cancel out on the right side:

2x + 6 = -6

Subtracting 6:

2x + 6 - 6 = -6 -6

The 6 and -6 are canceled out:

2x = -12

Dividing by 2:

x = -12/2

x = -6

8 0

3 years ago

If you divide 6! by 4! you are evaluating P(6, 4)

Aleks [24]

When you're evaluating P(n, k), you are essentially saying there are n objects and you will need to arrange them in k spaces.

This is essentially the same as: $^{6}P_4$ , which follows the formula:

$P(6, 4) = ^{6}P_4 = \frac{6!}{(6 - 4)!} = \frac{6!}{2!}$
If you're dividing by 4!, you are evaluating P(6, 2)

8 0

3 years ago

Multiply each equation by a constant that would help to eliminate the y terms. 2x-5y=-21 3x-3y=-18 What are the resulting equati

anyanavicka [17]

Answer:

6x - 15y = -63

15x -15y = -90

Step-by-step explanation:

We need to multiply the two equations by a constant that will eliminate the y terms.

The two equations are:

2x - 5y = -21

3x - 3y = -18

Let us multiply the first by 3 and the second by 6. The resulting equations will be:

6x - 15y = -63

15x -15y = -90

Note: To solve the system of equations we can simply subtract the first from the second.

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3 years ago