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sertanlavr [38]
3 years ago
5

I need help is it A B C or D

Mathematics
1 answer:
MissTica3 years ago
6 0
I believe it is A. hopefully
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Can you please help me out and when you do it please the division house
Zolol [24]

Answer:

115.75

Step-by-step explanation:

463/4 friends = 115.75

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4 years ago
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Which of the following equations has the same solutions as the equations 3x+2y=-12
Marianna [84]

B, C, E, F

<h2>Explanation:</h2>

In this problem, we have the following equation of a line written in Standard form:

3x+2y=-12

So  we need to choose the equations that has the same solutions as this equation. If we multiply each equation by a constant term and find the same solution as the given equation, then they will have the same solution. This is only true fro options B, C, E and F.

Option B.

-3x-2y= 12 \\ \\ Multiply \ both \ sides \ by \ -1: \\ \\ (-1)(-3x-2y)=(-1)(12) \\ \\ 3x+2y=-12

So we get the same given equation. This option is valid!

Option D.

15x+10y= -60 \\ \\ Multiply \ both \ sides \ by \ 1/5: \\ \\ (\frac{1}{5})(15x+10y)=(\frac{1}{5})(-60) \\ \\ 3x+2y=-12

So we get the same given equation. This option is valid!

Option E.

6x+2y= -12 \\ \\ Multiply \ both \ sides \ by \ 1/2: \\ \\ (\frac{1}{2})(6x+2y)=(\frac{1}{2})(-24) \\ \\ 3x+2y=-12

So we get the same given equation. This option is valid!

Option F.

1.5x+y= -6 \\ \\ Multiply \ both \ sides \ by \ 2: \\ \\ (2)(1.5x+y)=(2)(-6) \\ \\ 3x+2y=-12

So we get the same given equation. This option is valid!

For the other options, there is no any constant term that multiplies both sides of the equation and gives us the same given equation.

<h2>Learn more:</h2>

About this subject: brainly.com/question/8810210

#LearnWithBrainly

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3 years ago
What is the volume of this cube?
jolli1 [7]

Answer:

v=a3

Step-by-step explanation:

the internet told me

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What is 97/50 as a decimal
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97/50 would be multipled by 2 to get 0.196. You multiply by 2 to make it easier
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What is the x intercept of the line y=5x+6
garri49 [273]
Check out Desmos.com graphing calculator if you need help with graphing
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