Answer:
.375
Step-by-step explanation:
a ball is dropped from a height of 20 feet above the ground. The velocity v(s) of the ball after it has travelled a distance of
1 answer:
<h2>We know that</h2>
The initial height is 20 feet above the ground.
The function to model the velocity is
Where <em>s</em> represents the distance in feet.
Mathematically, this function has all real numbers as a domain. However, that will no make sense for this situation, because it would use negative numbers for the distance <em>s</em> which does not make sense.
Therefore, the domain, in this case, would be all real numbers greater than or equal to zero, but less than or equal to 20.
<em>The reason for this domain is that the ball will go from 20 feet above the ground to zero feet on the ground.</em>
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Using interval notation would be
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Answer:
Step-by-step explanation:
The system of equations is;
-12x-13y +13z =15
7x-10y-3z = 11
7x+14y +5z = -5
The coefficient matrix is
The constant matrix is
The augmented matrix is
Answer:
The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.
Step-by-step explanation:
According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.
Then, the mean of the distribution of the sum of values of X is given by,
And the standard deviation of the distribution of the sum of values of X is given by,
The information provided is:
<em>μ</em> = $970
<em>σ</em> = $129
<em>n</em> = 102
Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.
Then,
Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:
*Use a <em>z</em>-table for the probability.
Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.