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2 years ago

Determine the unit rate. A 4-pound bag of yarn costs $7.56.

Mathematics

1 answer:

Verizon [17]2 years ago

3 0

Answer:

work is shown and pictured

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What is the best approximate solution of the system of linear equation y=1.5x - 1 and y=1

kiruha [24]

1 = 1.5x -1
+1 +1
2 = 1.5x
/1.5 /1.5
4/3 = x

y = 1.5 ( 4/3 ) -1
y = 1

solution:
x = 4/3
y = 1

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2 years ago

Dustin had five outstanding checks that totaled $117.54. What should his check register balance be if he had an ending balance o

shusha [124]

Ending balance $599.43
outstanding deposit $235.14 +
total $834.57
outstanding check $117.54 -
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hope this help

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2 years ago

What is the answer to 5-10x<-145

Nuetrik [128]

Answer:

x > 15

Step-by-step explanation:

So here we have to find the value of x

So, Subtract 5 from both sides;

-10x < -5 - 145

Now collect like terms,

-10x < -150

Divide both sides by -10

x > 15

The sign changes because if an equality is divided by a negative number the sign automatically changes.

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2 years ago

What is the equation of the circle with center (-3.2,2.1) and radius 4.3?

Nutka1998 [239]

$(x+3.2)^2+(y-2.1)^2=4.3^2$

8 0

2 years ago

Read 2 more answers

Which expressions have a value of 16/81? Check all that apply.

lana [24]

Which expression have a value of 16/81? check all that apply. (2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2

Answer:

First and last option is correct.

$(\frac{2}{3})^{4}=\frac{16}{81}$

$(\frac{4}{9})^{2}=\frac{16}{81}$

Step-by-step explanation:

Given:

There are four options.

(2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2

We need to check all given options for value of 16/81.

Solution:

Using rule.

$(\frac{a}{b})^{n}=\frac{a^{n}}{b^{n}}$

Solve for option $(\frac{2}{3})^4$ .

$(\frac{2}{3})^{4}=\frac{2^4}{3^4}=\frac{2\times 2\times 2\times 2}{3\times 3\times 3\times 3}=\frac{16}{81}$

Solve for option $(\frac{16}{3})^4$ .

$(\frac{16}{3})^{4}=\frac{16^4}{3^4}=\frac{16\times 16\times 16\times 16}{3\times 3\times 3\times 3}=\frac{65536}{81}$

Solve for option $(\frac{4}{81})^2$ .

$(\frac{4}{81})^{2}=\frac{4^2}{81^2}=\frac{4\times 4}{81\times 81}=\frac{16}{6561}$

Solve for option $(\frac{4}{9})^2$ .

$(\frac{4}{9})^{2}=\frac{4^2}{9^2}=\frac{4\times 4}{9\times 9}=\frac{16}{81}$

Therefore, expression $(\frac{2}{3})^4$ and $(\frac{4}{9})^2$ have a value of $\frac{16}{81}$ .

6 0

2 years ago