Answer:
Go 6 units to the right and then 8 units up.
Answer:
The proportion of student heights that are between 94.5 and 115.5 is 86.64%
Step-by-step explanation:
We have a mean 
and a standard deviation 
. For a value x we compute the z-score as 
, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%
Answer: the answer would be 4.5
Step-by-step explanation:
she walks 3 miles every 80 minutes and 80 plus 80 would be 160 but this is 120 so it would be 80 plus 40 so its half of 80 so half of 3 is 1.5 so there, hopes this helps
No because u cant get the same answer by measuring with a half inch
