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Alenkasestr [34]
2 years ago
9

A heavy bank-vault door is opened by the application of a force of 3.0 x 102 N directed perpendicular to the plane of the door a

t a distance of 0.80 m from the hinges. What is the torque?
120 N·m
240 N·m
300 N·m
360 N·m
Mathematics
1 answer:
gogolik [260]2 years ago
8 0
For this question, we need  the formula τ = F x d<span>, and just plug the numbers in.

</span>

Given the formula <span>τ = F x d</span>
Where τ = torque,
F = force applied, &
d = distance from the axis / hinge,

<span>τ = 300 c 0.8 = 240Nm</span>

Disregard the weight of the door or if there's any friction at the hinge. None of this will change the torque applied.

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The length of a rectangle is 11 centimeters less than six times its width. Its area is 21 square centimeters. Find the dimension
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The width is 3cm, and the length is 7cm.

Step-by-step explanation:

Let's call the length of the rectangle l, the width of the rectangle w, and the area of the rectangle A, and write down everything we know about them.

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We can rearrange this new equation to get everything on the same side, so that we have a standard quadratic equation, like this:

6w^2 - 11w - 21 = 0.

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w = \frac{11\pm\sqrt{121+504}}{12}\\\\{}\hspace{0.25cm}=\frac{11\pm\sqrt{625}}{12}\\\\{}\hspace{0.25cm}=\frac{11\pm25}{12}.

With a little further cancellation, we can find our two possible values of w are

w = \frac{36}{12} = 3  and w = \frac{-14}{12}.

Since w is a width of a rectangle, it can't possibly be negative, and so it must be 3.

We can now plug in this value into our equation from earlier, namely l = 6w - 11. We can see that

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We can prove that this is right by multiply 3 and 7 together, and seeing that we get 21, the area we expect.

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