the problem would be set up as 6+(7*x)=41
first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41
7x =41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 =5.9
so x =5.9
Answer:
12.
Step-by-step explanation:
This is how to round 12.36 to the nearest whole number. In other words, this is how to round 12.36 to the nearest integer.
12.36 has two parts. The integer part to the left of the decimal point and the fractional part to the right of the decimal point:
Integer Part: 12
Fractional Part: 36
Our goal is to round it so we only have an integer part using the following rules:
If the first digit in the fractional part of 12.36 is less than 5 then we simply remove the fractional part to get the answer.
If the first digit in the fractional part of 12.36 is 5 or above, then we add 1 to the integer part and remove the fractional part to get the answer.
The first digit in the fractional part is 3 and 3 is less than 5. Therefore, we simply remove the fractional part to get 12.36 rounded to the nearest whole number as:
12
The slope of line q is that of line p scaled by a factor of 3 (not -3). The y-intercept of line q is 6 less than the y-intercept of line p. The appropriate choice is
D. y = 3ax +b -6
I= sqrt (-1)
If the power is
- even then the value could be -1 or 1
-odd then the value could be -i or i
99 is odd so now is
-i if (99+1)/2 is even or is
i is (99+1)/2 is odd
Now check (99+1)/2= 100/2= 50,
50 is even so
i^99 = -i
Answer:
363
Step-by-step explanation:
0.66*550=363
