-x+4y=5 find an ordered pair that is a solution to the equation
1 answer:
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<u>Step-by-step explanation:</u>
The vertex form of an absolute value equation is: where
(h, k) is the vertex. In the given equation, , the h-value is 1/2 and the k-value is -2.
So, the vertex (h, k) = (1/2, -2)
f(x) = 2 -4x
Step-by-step explanation:
Step 1 :
Given, f(x) = a(x - h)2 + k
Point on the parabola is (3, 6)
Vertex (h,k) = (1,-2)
Step 2:
Substituting the vertex in the equation we have,
f(x) = a(x-1)2 -2
Substituting the point (3,6) in this we have,
6 = a(3-1)2 - 2 => 6 = 4a -2
=> 4a = 8 => a = 2
Step 3 :
Substituting the value for a and the vertex in the given equation we have
f(x) = 2(x-1)2 -2 = 2(x2 - 2x + 1) -2 = 2x2 - 4x
=> f(x) = 2 -4x which is the standard form