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3 years ago

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Find the equation f(x) = a(x - h)2 + k for a parabola containing point (3, 6) and having (1, -2) as a vertex. What is the standa

rd form of the equation?

1 answer:

nlexa [21]3 years ago

8 0

f(x) = 2 $x^{2}$ -4x

Step-by-step explanation:

Step 1 :

Given, f(x) = a(x - h)2 + k

Point on the parabola is (3, 6)

Vertex (h,k) = (1,-2)

Step 2:

Substituting the vertex in the equation we have,

f(x) = a(x-1)2 -2

Substituting the point (3,6) in this we have,

6 = a(3-1)2 - 2 => 6 = 4a -2

=> 4a = 8 => a = 2

Step 3 :

Substituting the value for a and the vertex in the given equation we have

f(x) = 2(x-1)2 -2 = 2(x2 - 2x + 1) -2 = 2x2 - 4x

=> f(x) = 2 $x^{2}$ -4x which is the standard form

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4 years ago

Brianna has x nickels and y pennies. She has no less than 20 coins worth no more

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Answer:

$y \ge 20 - x$

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Step-by-step explanation:

Given

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Required

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3 years ago

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Answer:

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The rule is, in order to add fractions, your denominators must be equivalent. In other words, you must have the same denominator for both fractions.

<em>Now what do we do? We add!</em>

$\frac{1}{6} + \frac{4}{6} =\frac{5}{6}$

This is because 4 + 1 = 5.

Your answer is $\frac{5}{6}$ .

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

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