1)
LHS = cot(a/2) - tan(a/2)
= (1 - tan^2(a/2))/tan(a/2)
= (2-sec^2(a/2))/tan(a/2)
= 2cot(a/2) - cosec(a/2)sec(a/2)
= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))
= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)
= 2[(1+cos(a) -1)/sin(a)]
=2cot a
= RHS
2.
LHS = cot(b/2) + tan(b/2)
= [1 + tan^2(b/2)]/tan(b/2)
= sec^2(b/2)/tan(b/2)
= 1/sin(b/2)cos(b/2)
using product to sums
= 2/sin(b)
= 2cosec(b)
= RHS
Answer: 108 ft³
Step-by-step explanation:
V= 4/3πr³
Facts:
Pi= 3
Diameter = 6
Step1; find the radius
Diameter is the length acaross the whole circle, but the radius is just 1/2 the circle. Therefore, if the diameter is 6, then the radius can be found by finding 1/2 of 6.
1/2 of 6= 1/2x6= 3.
R= 3
Step 2: Plug in the numbers (into the formula)
PEMDAS
(exponents go first)
(then multiply from left to right)
V= 4/3πr³
V= 4/3x3x3³
V= 4/3x3x (3x3x3)
V= 4/3x3x27
V= (4/3x3) x 27
V= 12/3x27
V= 4x27
V= 108
<u><em>Volume= 108 ft³ </em></u>
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Hope this helps :)) Also brainliest would be appreciated, i worked pretty hard on this thanks! :)
Hey there!
There are 2.20462 pounds in a kilogram
