Question

1. A 2012 survey conducted by the local paper in Columbus, Ohio one week before Election Day

Answer 1

Answer:

The description again for the problem is listed throughout the section below on explanations.

Step-by-step explanation:

A 2012 survey conducted a week since Voting day because the local paper in Columbus asked voters whatever individual they might vote for the state attorney. 37% of respondents said that they'd vote for both the dem candidate. In reality, 41 percent voted for both the Democratic nominee on Elections Day.

The 37% is supported by a survey as well as being a factual estimate. The sample proportion is denoted by "P". Therefore,

⇒  P = 0.37

The specific proportion becomes supplied as a factor of 41% = 0.41. Since the importance of proportion is real.  The proportion of community is represented as p or π

Hence p = 0.41.