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Anna71 [15]
3 years ago
10

If , find the value of 2 square root of 17-x = 2x-10, find the value of x/4.

Mathematics
1 answer:
ira [324]3 years ago
7 0
2 \sqrt{17-x} =2x-10\ \ \ \ \Rightarrow\ \ \ D:(17-x \geq 0\ \ \ and\ \ \ 2x-10 \geq 0)\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \leq 17\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ x \geq 5\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=\\\\2 \sqrt{17-x} =2(x-5)\ /:2\\\\ \sqrt{17-x} =x-5\ \ \ \Rightarrow\ \ \ (\sqrt{17-x})^2 =(x-5)^2\\\\17-x=x^2-10x+25\\\\

x^2-9x+18=0\\\\ x^2-3x-6x+18=0\\\\x(x-3)-6(x-3)=0\\\\(x-3)(x-6)=0\ \ \ \ \Leftrightarrow\ \ \ (x-3=0\ \ \ \ or\ \ \ \ x-6=0)\\\\x=3\ \notin\ D\ \ \ \ \ \ \ \ \ \ \ x=6\ \in\ D\ \ \ \Rightarrow\ \ \  \frac{x}{4} = \frac{6}{4} =1.5\\\\Ans.\  \frac{x}{4} =1.5
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vagabundo [1.1K]
No, the longest side must be less than the sum of the smaller sides or else they won't connect (try it yourself with straw or something)

40+30>120
70>120
false, therfor they canonot be a triangle
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3 years ago
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1.64 as a fraction in simplest form
mrs_skeptik [129]
<span>The correct answer is 1 16/25.

Explanation<span>:
This is read as "one and sixty-four one-hundredths." This means the fraction would be 1 64/100.

Both numerator and denominator are even, so we will divide both by 2 and get 1 32/50.

Again, both are even, so we divide by 2 again and get 1 16/25.</span></span>
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What is 0.096 in word for
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Which expression can be used to find the surface area of the following triangular prism?
Orlov [11]

Answer:

214.

Step-by-step explanation:

To get Surface area take

(cross section area) × 2 +(perimeter of crossection area × length)

the cross section area is a triangle

so area of a triangle =1/2 base times height

1/2×8×2=8

let's get perimeter of cross section

the cross section is still at triangle so let's find its perimeter.

5+5+8=18

18×length of which is 11

18×11=198

and 188 + 16=214. that's the answer

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6 0
3 years ago
Simplify 5+2i/6+i
nlexa [21]

Given problem is \frac{(5+2i)}{(6+i)}

To simplify that we need to multiply and divide by conjugate of the denominator

conjugate of denominator 6+i will be 6-i as we just need to change sign of the imaginary part

Now multiply and divide by 6-i


=\frac{(5+2i)}{(6+i)}\cdot\frac{(6-i)}{(6-i)}

=\frac{30-5i+12i-2i^2}{36-6i+6i-i^2}

=\frac{30+7i-2i^2}{36-i^2}

=\frac{30+7i-2\left(-1\right)}{36-\left(-1\right)}

=\frac{30+7i+2}{36+1}

=\frac{32+7i}{37}

=\frac{32}{37}+\frac{7}{37}i

Hence final answer is \frac{32}{37}+\frac{7}{37}i

3 0
3 years ago
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