Answer:
Step-by-step explanation:
For the null hypothesis,
µ = 60
For the alternative hypothesis,
h1: µ < 60
This is a left tailed test
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 100,
Degrees of freedom, df = n - 1 = 100 - 1 = 99
t = (x - µ)/(s/√n)
Where
x = sample mean = 52
µ = population mean = 60
s = samples standard deviation = 22
t = (52 - 60)/(22/√100) = - 3.64
We would determine the p value using the t test calculator. It becomes
p = 0.00023
We would reject the null hypothesis if α = 0.05 > 0.00023
I do know the bottom one is 2.8
Top is 1.6
I don’t know the middle one
We are given f(x) = 5x
and we are to find inverse of f(x).
Step 1:
Replace f(x) by y.
So,
y = 5x
Step 2:
Isolate x
So,
x = y/5
Step 3:
Replace x by f'(y)
So,
f'(y) = y/5
Step 4:
Replace all occurrences of y by x.
So,
f'(x) = x/5
Therefore, the inverse of f(x) = 5x is f'(x) = x/5
-5x - 15 > 10 + 20x...subtract 10 from both sides, add 5x to both sides
-10 - 15 > 20x + 5x ...simplify
-25 > 25x...divide both sides by 25
-25/25 > x ....reduce
-1 > x or x < -1 <===
so square root is really is easyyy put in 6.4 ♾️
