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2 years ago

34258 and 47163 the value of 4 in 47163 is blank times the value of 4 in 34258

Mathematics

1 answer:

Leto [7]2 years ago

3 0

Based on the question, the 4 in the second figure is 10 times larger in value than the 4 in the first figure.

<h3>How can the value be calculated?</h3>

If we check the "47163," which is the second number , we can see that 4 is in the ten-thousands position.

Then in the first figure, "34258," the value 4 is in the one-thousands position.

Therefore, Based on the question, the 4 in the second figure is 10 times larger in value than the 4 in the first figure.

Read more on the Revolutionary War battles of Trenton here:

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Answer:

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Step-by-step explanation:

Given,

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When,

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$x=0.1, F(0.1)=\frac{e^0.1-1-0.1}{(0.1)^2}=0.517091$

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$x=0.01, F(0.01)=\frac{e^0.01-1-0.01}{(0.01)^2}=0.501670 \hfill (1)$

Correct upto six decimal places.

Now,

$\lim_{x\to 0}F(x)=\lim_{x\to 0}\frac{e^x-1-x}{x^2}$ $(\frac{0}{0})$ form, applying L-Hospital rule that is differentiating numerator and denominator we get,

$\lim_{x\to 0}F(x)$

$=\lim_{x\to 0}\frac{e^x-1}{2x}$ $(\frac{0}{0})$ form.

$=\lim_{x\to 0}\frac{e^x}{2}=\frac{1}{2}=0.5\hfill (2)$

Limit exist and is 0.5. That is according to (1) we can see as the value of x lesser than 1 and tending to near 0, value of the function decreases respectively. And from (2) it shows ultimately it decreases and reach at 0.5, consider as limit point of F(x).

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