Write an appropriate direct variation equation if y = 8 when x = 4.

Mathematics

1 answer:

konstantin123 [22]3 years ago

4 0

The correct option would be: y = 2x

You can check by replacing the variables with the given values.

Hope this helps!

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A cyclist is stationary when a second cyclist passes travelling at a constant speed of 8 m s−1. The first cyclist then accelerat

DerKrebs [107]

Answer:

im not too sure about that sorry!

Step-by-step explanation:

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2 years ago

Two cars are heading toward the same intersection. Car A travels due east at 20 miles per hour, and Car B travels due north at 5

Genrish500 [490]

Answer:

the distance between them is decreasing at a rate of 2 mph.

Step-by-step explanation:

List all given rates and the unknown rate.

Write the formula that relates the variables in the problem: x, y, and s.

There’s a right triangle in the diagram, so you use the Pythagorean Theorem:

For this problem, x and y are the legs of the right triangle, and s is the hypotenuse, so

Differentiate with respect to t.

Use the Pythagorean Theorem again to solve for s.

x = 0.4

y = 0.3

You can reject the negative answer because s obviously has a positive length. So s = 0.5.

Now you’ve got everything you need to substitute into the differentiation result and solve for ds/dt.

This negative answer means that the distance, s, is decreasing. Thus, when car A is 3 blocks north of the intersection and car B is 4 blocks east of the intersection, the distance between them is decreasing at a rate of 2 mph.

3 0

3 years ago

Graph the system of equations on graph paper.

masha68 [24]

4. The x-coordinate of the solution is 9.
5. The y-coordinate of the solution is −8 .
6.The ordered pair that is the solution to the system lies in Quadrant IV .

Proof:

Solve the following system:
{4 x + 3 y = 12 | (equation 1)
{2 x + 3 y = -6 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:
{4 x + 3 y = 12 | (equation 1)
{0 x+(3 y)/2 = -12 | (equation 2)

Multiply equation 2 by 2/3:
{4 x + 3 y = 12 | (equation 1)
{0 x+y = -8 | (equation 2)

Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 36 | (equation 1)
{0 x+y = -8 | (equation 2)

Divide equation 1 by 4:
{x+0 y = 9 | (equation 1)
{0 x+y = -8 | (equation 2)

Collect results:

Answer: {x = 9 , y = -8