Answer:
Answer:
164.32 earth year
Step-by-step explanation:
distance of Neptune, Rn = 4.5 x 10^9 km
distance of earth, Re = 1.5 x 10^8 km
time period of earth, Te = 1 year
let the time period of Neptune is Tn.
According to the Kepler's third law
T² ∝ R³
Tn = 164.32 earth years
Thus, the neptune year is equal to 164.32 earth year.
Step-by-step explanation:
Answer:
what grade you in
Step-by-step explanation:
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Answer:
x = -2
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
8x + 4(x - 3) = 4(6x + ) -4
8x +(4)(x) + (4)(-3) = (4)(6x) + (4)(4) + -4 (distribute)
8x + 4x + -12 = 24x + 16 + -4
(8x) + (4x) +(-12) = (24x) + (16 + -4) (combine like terms)
12x + -12 = 24x + 12
12x -12 = 24x + 12
Step 2: Subtract 24x from both sides.
12x -12 -24x = 24x + 12 -24x
-12x -12 = 12
Step 3: Add 12 to both sides.
-12x - 12 + 12 = 12 + 12
-12x = 24
Step 4: Divide both sides by -12.
-12x/-12 = 24/-12 <u>x = -2</u>
HOPE THIS HELPED!!!
<span>At least one bear was sighted on 28 separate days in 40 day period total = 28/40
We're looking for the daily frequency of bear sightings, that's in the whole 40 day period.
Let's say 40 days period = 100%.
Then what's 28 days?
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So the solution we're looking for would be (<span><span>28 days∗100) / </span>40 days = 70%</span>
The final answer is B. 70%.
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