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Masteriza [31]
3 years ago
10

Mollie bought 12 packages of carrots for a total of $48. She realized she needed to purchase another 10 more packages. How much

will she have spent IN ALL on the carrots?
Mathematics
2 answers:
scoray [572]3 years ago
7 0

Answer:

$88

Step-by-step explanation:

48/12= 4

for another 10 she pays another $40

Phantasy [73]3 years ago
7 0

Answer:

$88

Step-by-step explanation:

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Two angles are supplementary. The measure of one angle is 4 more than 7 times the other angle. Find the measures of both angles.
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Answer:

<u>The smaller angle measures 44° and the larger measures 136°</u>

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Smaller angle = x

Larger angle = 3x + 4

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At an annual salary of $55,000 per year, what is the amount of semimonthly paychecks?
Amiraneli [1.4K]
Semi monthly means 2 times per month
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4 0
3 years ago
Simplify, 99/121 whats the GCF?
Nadya [2.5K]

To find the GCF:

-- List the factors of the first number.
-- List the factors of the second number.
-- Make a short list of the factors that show up for BOTH numbers.
-- Find the biggest number on the short list.

Factors of the first number (99):  <u>1</u>, 3, 9, <u>11</u>, 33, 99 .

Factors of the second number (121):  <u>1</u>, <u>11</u>, 121 .

Short list (factors that show up for both numbers):  1, 11

Biggest number on the short list:  <em>11</em>


3 0
3 years ago
12. Use a trigonometric ratio to find the measure of O in the triangle below. Give your answer to the nearest degree.
larisa [96]

<u>G</u><u>iven </u><u>:</u><u>-</u>

  • A right angled triangle with two sides 10cm and 9cm .

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The value of theta .

<u>Solution</u><u> </u><u>:</u><u>-</u>

At angle theta , 9cm side will be considered as the perpendicular and 10cm side will be hypotenuse . So , as we know that ;

\longrightarrow sin\theta =\dfrac{perpendicular}{hypotenuse}

Substituting the respective values,

\longrightarrow sin\theta =\dfrac{9cm}{10cm}

Simplify,

\longrightarrow sin\theta= 0.9

Take arcsin both sides ,

\longrightarrow \theta =sin^{-1}(0.9)

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