Use the formula of an area of a tringle:
![A=\dfrac{1}{2}bc\sin A](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7B1%7D%7B2%7Dbc%5Csin%20A)
We have b = 11 yd, c = 24 yd and m∠A = 67°
![A=\dfrac{1}{2}(11)(24)\sin67^o](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7B1%7D%7B2%7D%2811%29%2824%29%5Csin67%5Eo)
![\sin67^o\approx0.9205\\\A=(11)(12)(0.9205)=121.506\ yd^2](https://tex.z-dn.net/?f=%5Csin67%5Eo%5Capprox0.9205%5C%5C%5CA%3D%2811%29%2812%29%280.9205%29%3D121.506%5C%20yd%5E2)
Answer:
-0.05
Step-by-step explanation:
Given the expression :
0.1×( – 0.9+ – 0.2÷ – 0.5)
Evaluating the bracket :
0.1 * (-0.9 - 0.2 ÷ - 0.5)
Solving the division first
-0.2 ÷ - 0.5 = 0.4
Now we have ;
0.1 * (-0.9 + 0.4)
0.1 * - 0.5
= - 0.05
The height of the fifth bounce
80x65%x65%x65%x65%x65%
=9.282325 cm
Answer:
f(1)=4
Step-by-step explanation:
f(1)=3(1)^4-(1)^2+4(1)-2
f(1)=3(1)-1+4-2
f(1)=3-1+4-2
f(1)=4
Answer:
The answer is
<h2>
![y = - \frac{6}{5} x - 3 \\](https://tex.z-dn.net/?f=y%20%3D%20%20-%20%20%5Cfrac%7B6%7D%7B5%7D%20x%20-%203%20%5C%5C%20)
</h2>
Step-by-step explanation:
To find an equation of a line when given the slope and a point we use the formula
![y - y_1 = m(x - x_1) \\](https://tex.z-dn.net/?f=y%20-%20%20y_1%20%3D%20m%28x%20-%20%20x_1%29%20%5C%5C%20)
where
m is the slope
( x1 , y1) is the point
From the question the point is (5, -6) and slope - 3/5
The equation of the line is
![y + 6 = - \frac{3}{5} (x - 5) \\ y + 6 = - \frac{3}{5} x + 3 \\ y = - \frac{6}{5} x + 3 - 6](https://tex.z-dn.net/?f=y%20%2B%206%20%3D%20%20-%20%20%5Cfrac%7B3%7D%7B5%7D%20%28x%20-%205%29%20%5C%5C%20y%20%2B%206%20%3D%20%20-%20%20%5Cfrac%7B3%7D%7B5%7D%20x%20%2B%203%20%5C%5C%20y%20%3D%20%20-%20%20%5Cfrac%7B6%7D%7B5%7D%20x%20%2B%203%20-%206)
We have the final answer as
![y = - \frac{6}{5} x - 3 \\](https://tex.z-dn.net/?f=y%20%3D%20%20-%20%20%5Cfrac%7B6%7D%7B5%7D%20x%20-%203%20%5C%5C%20)
Hope this helps you