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ra1l [238]
3 years ago
9

PLEASE HELP ME me me me​

Mathematics
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

Andre has the correct answer. When simplified his answer is equivalent to the original equation.

allsm [11]3 years ago
6 0

Answer:

2pg1

Step-by-step explanation:

Hehe

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What is the measure of arc qr?
ella [17]
Angle QSR is an inscribed angle and is equal to half the intercepted arc.
So if angle QSR = 52 degrees then the arc measures 104 degrees.
Source: http://www.1728.org/circangl.htm
(Look at the first graphic).

4 0
3 years ago
Read 2 more answers
Find a polynomial function of degree 3 with real coefficients that has the given zeros. -1, 2, -8 The Polynomial function is f(x
lakkis [162]
The zeros are -8, -1, 2, so you can write the function as f(x)=(x-(-8))(x-(-1))(x-2)=(x+8)(x+1)(x-2).

Expand:
(x+8)(x+1)(x-2)= \\
(x^2+x+8x+8)(x-2)= \\
(x^2+9x+8)(x-2)= \\
x^3-2x^2+9x^2-18x+8x-16= \\
x^3+7x^2-10x-16

The function is f(x)=x³+7x²-10x-16.
The missing value is 7.
5 0
3 years ago
. Write an equation of the line that passes through the given points use point
Damm [24]

Answer:

y = \frac{1}{3}x+\frac{1}{3}

Step-by-step explanation:

First, we need to figure out a linear equation. When given two points - (x_{1}, y_{1})and (x_{2}, y_{2}) - first subtract y_{1} from y_{2} and and x_{1} from x_{2}. So in your situation, it will be 2-1 and 5-2. That equals 1 and 3, so your slope (how much the line moves up/down per unit) will be \frac{1}{3} x.

Next, we need to find the y-intercept. To solve using point-slope form, we will plug our numbers in:

y-y_{1} = m(x-x_{1})\\y-1=\frac{1}{3}(x-2)\\y-1=\frac{1}{3}x-\frac{2}{3}\\/+1=//+1\\y = \frac{1}{3}x+\frac{1}{3}

So our final equation is y = \frac{1}{3}x+\frac{1}{3}, which passes through both (2,1) and (5,2). Hope this helps :)

3 0
3 years ago
For the rational equation x
zlopas [31]
It is indeed the rearranging of neuritis to the ground.
5 0
3 years ago
Select the figure obtained when rotating the figure about an axis along its largest side, and find the exact surface area of the
Talja [164]

Answer:

Figure obtained - Cylinder

Surface area of the cylinder is 1224π square units.

Step-by-step explanation:

When a rectangle is rotated about an axis along its largest side, a cylinder having radius 17 and height 19 units is formed.

Surface area of the cylinder = 2πr(h + r)

By substituting r = 17 units and h = 19 units in the given formula,

Surface area = 2π(17)(17 + 19)

                     = (34)(36)π

                     = 1224π

Therefore, surface area of the cylinder is 1224π square units.

4 0
3 years ago
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