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3 years ago

8

in a college library there are 4 times as many nonfiction books as fiction books.find the ration of non fiction books to the no

.of fiction books

2 answers:

Stolb23 [73]3 years ago

5 0

Ok. how many fiction books are there?

umka21 [38]3 years ago

5 0

The ratio would have to be 4:1 4 being the nonfiction and the 1 being the fiction

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liraira [26]

Step-by-step explanation:

The turning point of a quadratic function is equidistant from both x-intercepts (if they exist)

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3 years ago

What is the respond for 4(b-6)+19

vlabodo [156]

So I think you’re asking for the solution to the equation mentioned.

The answer would be 4b-5

Explanation:
Steps:

4(b-6)+19

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Standard form is, hold a sec

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if p<0 then pareabola opens left

so
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3 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

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3 years ago

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Ilia_Sergeevich [38]

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3 years ago