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3 years ago

Help! i need the answer to this

Mathematics

1 answer:

emmasim [6.3K]3 years ago

4 0

Answer:

Yes

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 270°

a point (x, y ) → (y, - x )

Thus

A(1, 1 ) → A'(1, - 1 )

B(1, 4 ) → B'(4, - 1 )

C(3, 4 ) → C'(4, - 3 )

D(6, 1 ) → D'(1, - 6 )

These are the correct coordinates for the diagram A'B'C'D'

A translation (x, y ) → (x + 4, y + 1 )

Add 4 to the x- coordinates and add 1 to the y- coordinates, that is

A'(1, - 1 ) → A''(1 + 4, - 1 + 1 ) → A''(5, 0 )

B'(4, - 1 ) → B''(4 + 4, - 1 + 1 ) → B''(8, 0 )

C'(4, - 3 ) → C''(4 + 4, - 3 + 1 ) → C''(8, - 2 )

D'(1, - 6 ) → D''(1 + 4, - 6 + 1 ) → D''(5, - 5 )

These are the correct coordinates for the diagram A''B''C''D''

Hence the composition of transformations is correct

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Which of these describes the unit rate?

AlexFokin [52]

Answer:

Which of these describes the unit rate? answer choices. a unit of measure. a fraction with a numerator of one. a fraction with a denominator of one. a proportion.

Step-by-step explanation:

Hope this helps you!

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5 0

3 years ago

Paul drove 225 miles to visit his parents. The graph below shows the distance traveled and the total time of the trip. Write and

ziro4ka [17]

50mph

Step-by-step explanation:

The image of the motion of Paul's derive is attached already.

From the line graph we can obtain a lot of information that will help us unravel the average speed of Paul within the given time frame.

What is average speed?

Average speed is the rate of change of total distance covered with time taken .

Average speed = $\frac{total distance }{time}$

To find the total distance covered;

Distance at time 1 = 75miles

Distance at time 4 = 225miles

Distance covered between 1 - 4 = 225 - 75 = 150miles

Time taken for the journey = 4 - 1 = 3hrs

Input the values in the equation;

Average speed = $\frac{150}{3}$ = 50mph

learn more:

Speed and motion brainly.com/question/10048445

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4 years ago

20 POINTS!!! PLZ ANSWER!! On the moon, the time, in seconds, it takes for an object to fall a distance, d, in feet, is given by

scoundrel [369]

Answer:

Part a) $f(2)=1.57\ sec$

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) see the explanation

Part c) $2,165.43\ sec$

Step-by-step explanation:

Let

f(d) -----> the time in seconds it takes for an object to fall

d -----> distance in feet

we have

$f(d)=1.11\sqrt{d}$

Part a): Determine f(2) and explain what it represents

we know that

f(2) represent the time in seconds it takes for an object to fall a distance of 2 feet

For $d=2\ ft$

substitute in the function above and solve for f(2)

$f(2)=1.11\sqrt{2}$

$f(2)=1.57\ sec$

therefore

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) The imbrium basin is the largest basin on the moon. A reasonable domain for the height above the lowest point in the basin is given by {d|0 ≤ d ≤ 3805774}

What does this tell you about the basin?

The height of the basin is greater than or equal to 0 ft and less than or equal to 3,805,774 ft

The maximum height of the basin is 3,805,774 ft

Part c) How long would it take a rock to drop from the rim to the bottom of the basin?

we know that

The distance from the rim to the bottom of the basin is equal to the maximum height of the basin

$d=3,805,774\ ft$