Question

X^2 - 6x + 1 = 0 by completing the square​

Answer 1

Answer:

See below.

Step-by-step explanation:

x^2 - 6x + 1 = 0

x^2 - 6x = -1

We halve the coefficient of  x (which is -6/2 = -3) and square it, then add this to both sides:-

x^2 - 6x + (-3)^2 = -1 + (-3)^2

x^2 - 6x + 9 = -1 + 9

(x - 3)^2 = 8

x - 3 = ±√8

x =  3 ± √8

= 0.17, 5.83   to 2 decimal places.

Answer 2

Answer:

$x = - 2 \sqrt{2} + 3 \\ or \\ x = 2 \sqrt{2 } + 3$