Question

Write the equation of the circle that has a diameter with endpoints (6,-1) and (0,-7).

Answer 1

$d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}}$
$d = \sqrt{(0 - (-1))^{2} + (-7 - (-1))^{2}}$
$d = \sqrt{(0 + 1)^{2} + (-7 + 1)^{2}}$
$d = \sqrt{(1)^{2} + (-6)^{2}}$
$d = \sqrt{1 + 36}$
$d = \sqrt{37}$
$d = 6.083$