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Alenkinab [10]
3 years ago
12

6w^2-11w-35 I need to factor the problem

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
8 0
6w^2 - 21w + 10w - 35
3w( 2w - 7) + 5 ( 2w - 7)
(3w + 5) ( 2w - 7)

This is the factorised form.
sergij07 [2.7K]3 years ago
3 0
Hello :
 <span>6w²-11w-35
</span><span>Δ = b²-4ac    a = 6        b= -11          c = -35
</span><span>Δ = (-11)² -4(6)(-35) =121 +840 = 961=31²
w1 = (11-31)/12 = -20/12 = -5/3
w2 = (11+31)/12 =42/12 =7/2
</span> 6w²-11w-35 =6(w-w1)(w-w2) = 6(w+5/3)(w-7/2)
<span>                                               = 1/2(6w+10)(2w-7)

</span> 6w²-11w-35  =(3w+5)(2w-7)<span>

</span>


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