Answer: Fourth option is correct.
Step-by-step explanation:
Since we have given that
Number of passengers for first car can hold = 6
Number of passengers for second car can hold = 3
According to question, If the ride designer wants to make sure that each run holds at least 12 passengers.
Let the number of 6 passengers cars be 'x'.
Let the number of 3-passengers cars be 'y'.
So, our equation becomes,
Put x = 0, y= 0
So, it becomes 0≥4 which is false.
So, it is shaded away from the origin.
At x= 0, y≥4
at y = 0, x≥6
Hence, Fourth option is correct.
THE NUMBERS ARE:
1
2
3
4
ALL 1 DIGIT NUMBERS BELOW 4
hope it helps!
Answer:
answer is 230
Step-by-step explanation:
they need more than 800 so u take 800-571 which is 229 u then add one because u need at least one more than 800 which is 230.
The answer is bc cause you multiply 12 x 2= 24
Answer:
x = -0.62 and x = 4.29
These values are approximations !
Step-by-step explanation:
You can not use Factoring to solve this equation. Perhaps you did not use the exact notation as in the original question?
Anyway, to solve it, you can still use the ABC formula.
3x²-11x-6=0
a = 3
b =-11
c = -6
x = [11 + √{121 -4(3 *-6)} ]/ 2*3
x = [11 + √{121 -4(-24)} ]/ 6
x = [11 + √{121 + 96} ]/ 6
x = [11 + √{217} ]/ 6
x = 4.29 This is an approximation !
x = [11 - √{121 -4(3 *-6)} ]/ 2*3
x = [11 - √{121 -4(-24)} ]/ 6
x = [11 - √{121 + 96} ]/ 6
x = [11 - √{217} ]/ 6
x = -0.62 This is an approximation !
extra: see the graph.
