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IceJOKER [234]
4 years ago
5

Which expression can be used to find the number of liters in 15 quarts?

Mathematics
2 answers:
4vir4ik [10]4 years ago
7 0

Answer:

15 liters = 15.85035 quarts

Step-by-step explanation:

1 liter = 1.05669 quarts

15 liters = 1.05669*15


gavmur [86]4 years ago
3 0
1 L, l = 1.0566882094 qt (US)
1 qt (US) = 0.946352946 L, l

Example: convert 15 L, l to qt (US):
15 L, l = 15 × 1.0566882094 qt (US) = 15.8503231415 qt (US)
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What is the correct answer for -16 = -8(n - 6)
ser-zykov [4K]

Answer: n=8

Step-by-step explanation:

-8(n-6)=-16

-8n+48=-16

-8n=-64

n=8

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4 years ago
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Answer:

Sheet metal costs <u>$20</u> per square foot.

Step-by-step explanation:

7.6x - 2.3x = 106

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3 years ago
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The sides of a square are increased by a scale factor of 6. The perimeter of the smaller square is 10 ft. What is the perimeter
inn [45]

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60ft

Step-by-step explanation:

I have not  done this kind of work in a while but if you scale each side of the square by 6 is should increase to a perimeter of 60ft

4 0
3 years ago
Find the equation for the line that passes through the point (4,2) that is parallel to the line with the equation
siniylev [52]

Step-by-step explanation:

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8 0
3 years ago
Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows
koban [17]

Answer:

The amount of Polonium-210 left in his body after 72 days is 6.937 μg.

Step-by-step explanation:

The decay rate of Polonium-210 is the following:

N(t) = N_{0}e^{-\lambda t}     (1)

Where:

N(t) is the quantity of Po-210 at time t =?

N₀ is the initial quantity of Po-210 = 10 μg

λ is the decay constant  

t is the time = 72 d  

The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.    

First, we need to find the decay constant:

\lambda = \frac{ln(2)}{t_{1/2}}    (2)

Where t(1/2) is the half-life of Po-210 = 138.376 days

By entering equation (2) into (1) we have:

N(t) = N_{0}e^{-\frac{ln(2)}{t_{1/2}}*t}} = 10* \frac{99.498}{100}*e^{-\frac{ln(2)}{138.376}*72} = 6.937 \mu g    

Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.  

I hope it helps you!  

8 0
3 years ago
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