So we are given the probabilities of q and r:
p (q) = 0.12
p (r) = 0.25
p (q and r) = 0.03
Actually to find for p (q or r), this simply means to add
all the values of p (q). p (r) and p (q and r). If we are to draw a bubble
diagram, the p (q and r) is the bubble intersection p (q) and p (r). We know
that the word “OR” takes up all in the bubble diagram. Therefore:
p (q or r) = p (q) + p (r) + p (q and r)
Substituting the given values into the equation:
p (q or r) = 0.12 + 0.25 + 0.03
<span>p (q or r) = 0.40</span>
Answer:
10
Step-by-step explanation:
X = 10.7
X4=81
x4=3 to the power of 4
x=3
Answer:
3,432 m²
Step-by-step explanation:
The amount of aluminum in square meters needed to make the mailboxes = 1863(surface area of each mailbox)
Surface area of each mail box = ½(surface area of cylinder) + (Surface area of rectangular prism/box - area of the surface of the box that joins the half-cylinder)
✔️Surface area of ½-cylinder = ½[2πr(h + r)]
r = ½(0.4) = 0.2 m
h = 0.6 m
π = 3.14
Surface area of ½-cylinder = ½[2*3.14*0.2(0.6 + 0.2]
= 0.628(0.8)
Surface area of ½-cylinder = 0.5024 m²
✔️Surface area of the rectangular box/prism = 2(LW + LH + WH)
L = 0.6 m
W = 0.4 m
H = 0.55 m
Surface area = 2(0.6*0.4 + 0.6*0.55 + 0.4*0.55)
Surface area of rectangular box = 1.58 m²
✔️Area of the surface joining the half cylinder and the box = L*W = 0.6*0.4 = 0.24 m²
✅Surface area of 1 mailbox = (0.5024) + (1.58 - 0.24)
= 0.5024 + 1.34
= 1.8424
Amount of aluminum needed to make 1863 mailboxes = 1863 × 1.8424 = 3,432.3912
= 3,432 m²
