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Helga [31]
3 years ago
15

If a polygon is a triangle, then it is either acute or obtuse. Which is the hypothesis of the conditional?

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

idk cuh

Step-by-step explanation:

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Given: AB tangent to circle O at B, and secant through point A intersect the circle at points C and D. Find CD, if
azamat

Answer:

6 cm

Step-by-step explanation:

If you use Tangent-secant product (chapter reference), AB/AC = AD/AB so 4/2 = AD/4. AD = 8, CD = AD - AC = 8 - 2 = 6 cm.

3 0
3 years ago
Read 2 more answers
Determine which of the lines are parallel and which of the lines are perpendicular.
hichkok12 [17]
This would be easier for you if you put it in a graph
6 0
2 years ago
Please Help!!! I need -14+6=-8 in a addition sentence​
padilas [110]

Step-by-step explanation:

megan owes the bank 14 dollars, but she then deposits 6 dollars. she now owes the bank 8 dollars

6 0
2 years ago
68 * 27 - 81 + ? = 600
tankabanditka [31]

The missing term is -1155.

Step-by-step explanation:

Given expression is

68 * 27 - 81 + ? = 600

Let the missing term be x

68*27-81+x=600\\1836-81+x=600\\1755+x=600

Subtracting 1755 from both sides

1755-1755+x=600-1755\\x=-1155

Therefore,

The missing term is -1155.

Keywords: multiplication, addition

Learn more about multiplication at:

  • brainly.com/question/10364988
  • brainly.com/question/10435816

#LearnwithBrainly

8 0
3 years ago
A N S W E R Q U I C K P L E A S E
chubhunter [2.5K]

Answer:

1. A

2. D

3. D

Step-by-step explanation:

The standard form of a parabola is

y=\frac{1}{4p}(x-h)^2+k            ..... (1)

Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.

1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .

k-p=-8                   ...(a)

(h,k+p)=(-2,-6)

k+p=-6            .... (b)

h=-2

On solving (a) and (b),  we get k=-7 and p=1.

Put h=-2, k=-7 and p=1 in equation (1).

y=\frac{1}{4(1)}(x-(-2))^2+(-7)

y=\frac{1}{4}(x+2)^2-7

Therefore option A is correct.

2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .

k-p=5                   ...(c)

(h,k+p)=(2,1)

k+p=1            .... (d)

h=2

On solving (c) and (d),  we get k=3 and p=-2.

Put h=2, k=3 and p=-2 in equation (1).

y=\frac{1}{4(-2)}(x-(2))^2+(3)

y=-\frac{1}{8}(x-2)^2+3

Therefore option D is correct.

3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .

k-p=-3                   ...(e)

(h,k+p)=(0,-2)

k+p=-2            .... (f)

h=0

On solving (e) and (f),  we get k=-2.5 and p=0.5.

Put h=0, k=-2.5 and p=0.5 in equation (1).

y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)

y=\frac{1}{2}(x)^2-2.5

y=\frac{1}{2}(x)^2-\frac{5}{2}

Therefore option D is correct.

5 0
2 years ago
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