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choli [55]
3 years ago
5

If it's zero degrees outside today and it's supposed to be twice as cold tomorrow, how cold is it going to be?

Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0
If you mean 2*0, that is not actually possible, but if you are using Celsius scale, 0 degrees is actually 273 degrees above absolute zero, so twice as cold in Celsius would be -137 degrees. In Fahrenheit, absolute zero is -460 degrees, so twice as cold in Fahrenheit would actually be -230 degrees.
Lena [83]3 years ago
5 0
It's anybody's guess. "Twice as cold" is a meaningless phrase.
No reliable weatherman would ever forecast it.

"Cold" is not a thing, and it can't be measured.  "Cold" is just a
lack of heat, and it feels different to different people.


Here are some other things that can't be measured, for the same reason:

-- darkness  (lack of light)
-- quietness  (lack of sound)
-- loneliness  (lack of companionship)
-- poorness, poverty  (lack of resources) 
-- vacuum  (lack of pressure)

There are no units of measure for lack of something.
The only way to measure these things is to measure how much
light, sound, heat etc. there IS.  Then, if that seems low to you,
you'll say that it's dark, quiet, or cold.  
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Galina-37 [17]
This man would be an approximate 154 pounds. 
My math: 
6 divided into 165 gives me the unit rate. (27.5)
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5 0
3 years ago
A pole that is 2.6 m tall casts a shadow that is 1.03 m long. At the same time, a nearby tower casts a shadow that is 46.25 m lo
photoshop1234 [79]

Answer:

Therefore the height of the tower is 116.75 m.

Step-by-step explanation:

Given that a pole that is 2.6 m tall casts a shadow that is 1.03 m long.

Here the height of a object directly proportional to the shadow. It means

Height of the object ∝ shadow

Height of the object= k.shadow

[k is the proportional constant.]

\Rightarrow \frac{h}{s} =k    [Height of object is denoted by h and shadow is denoted by s]

Then,

\frac{h_1}{s_1} =k       [h₁ is the height of the pole and s₁is the length of the shadow]

Again for the tower

\frac{h_2}{s_2}=k      [h₂ is the height of the tower and s₂ is the length of the shadow]

Therefore,

\frac{h_1}{s_1}=\frac{h_2}{s_2} =k

\Rightarrow\frac{h_1}{s_1}=\frac{h_2}{s_2}............(1)

Given h_1 = 2.6 m  ,s_1=1.03m  and   s_2=46.25m

Putting the value of h_1,s_1 and s_2  equation (1)

\frac{2.6}{1.03}=\frac{h_2}{46.25}

\Rightarrow h_2 \times1.03= 2.6\times 46.25          [cross multiplication]

\Rightarrow h_2 = \frac{2.6\times 46.25}{1.03}

\Rightarrow h_2= 116.75

Therefore the height of the tower is 116.75 m.

3 0
3 years ago
Which expression is equivalent to x6 - 16x^2?
Mrac [35]

Answer:

x^2(x - 2)(x + 2)(x^2 + 4)

Step-by-step explanation:

x^6-16x^2

x^2\left(x^4-16\right)

x^2\left(x^2+4\right)\left(x+2\right)\left(x-2\right)

\boxed{\bold{HOPE \:IT \:HELPS!\: :)}}

6 0
3 years ago
Equiva<br> Select two ratios that are equivalent to 27: 9.
disa [49]

Answer:

Step-by-step explanation:

27/9=9/3=3/1

3 0
3 years ago
If x^2 -7x=30 and x&gt;0, what is the value of x-5
laila [671]

Answer:

5

Step-by-step explanation:

x^2-7x=30

x^2-7x-30=0

a = 1, b = -7, c = -30

sqrt(b^2-4ac)

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13

-b +/- 13

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20/2 = 10

-6/2 = -3

we know x>0, so it cant be -3. so now its just 10 - 5

3 0
3 years ago
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