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koban [17]
3 years ago
7

Two rectangles have corresponding sides in the ratio of 3 : 4. The larger rectangle has one side measuring 6 inches. What is the

measure of the corresponding side in the smaller rectangle?
a.
4.5 in
c.
12 in
b.
8 in
d.
18 in
Mathematics
1 answer:
Irina-Kira [14]3 years ago
8 0

Big Rectangle : Small Rectangle = 4 : 3


4 parts = 6 inches

1 part = 6 ÷ 4 = 1.5 inches

3 parts = 1.5 x 3 = 4.5 inches


Answer: Corresponding side of the smaller rectangle is 4.5 in (A)


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Arrange the numbers in the ascending order: 3/4,1/12,9/16,7/24
OLEGan [10]
Ascending means going up
First change into decimals
3/4=0.75
1/12=0.083
9/16=0.5625
7/24=0.291666…..

Start from smallest to largest number
0.291666…..,0.5625,0.75,0.083

Find their fractions
7/24,9/16,3/4,1/12

Answer:7/24,9/16,3/4,1/12
4 0
1 year ago
A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp
abruzzese [7]

Step-by-step explanation:

<em>"A total of 12 players consisting 6 male and 6 female badminton players are attending a training camp."</em>

<em />

<em>"(a) During a morning activity of the camp, these 12 players have to randomly group into six pairs of two players each."</em>

<em>"(i) Find the total number of possible ways that these six pairs can be formed."</em>

The order doesn't matter (AB is the same as BA), so use combinations.

For the first pair, there are ₁₂C₂ ways to choose 2 people from 12.

For the second pair, there are ₁₀C₂ ways to choose 2 people from 10.

So on and so forth.  The total number of combinations is:

₁₂C₂ × ₁₀C₂ × ₈C₂ × ₆C₂ × ₄C₂ × ₂C₂

= 66 × 45 × 28 × 15 × 6 × 1

= 7,484,400

<em>"(ii) Find the probability that each pair contains players of the same gender only. Correct your final answer to 4 decimal places."</em>

We need to find the number of ways that 6 boys can be grouped into 3 pairs.  Using the same logic as before:

₆C₂ × ₄C₂ × ₂C₂

= 15 × 6 × 1

= 90

There are 90 ways that 6 boys can be grouped into 3 pairs, which means there's also 90 ways that 6 girls can be grouped into 3 pairs.  So the probability is:

90 × 90 / 7,484,400

= 1 / 924

≈ 0.0011

<em>"(b) During an afternoon activity of the camp, 6 players are randomly selected and 6 one-on-one matches with the coach are to be scheduled.</em>

<em>(i) How many different schedules are possible?"</em>

There are ₁₂C₆ ways that 6 players can be selected from 12.  From there, each possible schedule has a different order of players, so we need to use permutations.

There are 6 options for the first match.  After that, there are 5 options for the second match.  Then 4 options for the third match.  So on and so forth.  So the number of permutations is 6!.

The total number of possible schedules is:

₁₂C₆ × 6!

= 924 × 720

= 665,280

<em>"(ii) Find the probability that the number of selected male players is higher than that of female players given that at most 4 females were selected. Correct your final answer to 4 decimal places."</em>

If at most 4 girls are selected, that means there's either 0, 1, 2, 3, or 4 girls.

If 0 girls are selected, the number of combinations is:

₆C₆ × ₆C₀ = 1 × 1 = 1

If 1 girl is selected, the number of combinations is:

₆C₅ × ₆C₁ = 6 × 6 = 36

If 2 girls are selected, the number of combinations is:

₆C₄ × ₆C₂ = 15 × 15 = 225

If 3 girls are selected, the number of combinations is:

₆C₃ × ₆C₃ = 20 × 20 = 400

If 4 girls are selected, the number of combinations is:

₆C₂ × ₆C₄ = 15 × 15 = 225

The probability that there are more boys than girls is:

(1 + 36 + 225) / (1 + 36 + 225 + 400 + 225)

= 262 / 887

≈ 0.2954

7 0
3 years ago
1) What is the universal set?
slamgirl [31]

Answer:

the set containing all objects or elements and of which all other sets are subsets.

Step-by-step explanation:

6 0
3 years ago
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Explain why f(x) = x2+4/x2-x-2 is not continuous at x = 2.
xxTIMURxx [149]

Answer: Option a.

Step-by-step explanation:

 Make the denominator equal to zero and solve for x:

Factor the quadratic equation. Find two number whose sum is -1 and whose product is -2. Then:

x^{2}-x-2=0\\(x-2)(x+1)=0\\x=2\\x=-1

Then, as you can see the value x=2 makes the denominator equal to zero and the division by zero does not exist. Therefore you can conclude that the function shown in the problem is not defined at x=2

The answer is the option a.

6 0
3 years ago
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Find the indicated probability. The weekly salaries of teachers in one state are normally distributed with a mean of $490 and a
Alecsey [184]

Given Information:

Mean weekly salary = μ = $490

Standard deviation of weekly salary = σ = $45

Required Information:

P(X > $525) = ?

Answer:

P(X > $525) = 21.77%

Step-by-step explanation:

We want to find out the probability that a randomly selected teacher earns more than $525 a week.

P(X > 525) = 1 - P(X < 525)\\\\P(X > 525) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\P(X > 525) = 1 - P(Z < \frac{525 - 490}{45} )\\\\P(X > 525) = 1 - P(Z < \frac{35}{45} )\\\\P(X > 525) = 1 - P(Z < 0.78)\\\\

The z-score corresponding to 0.78 from the z-table is 0.7823

P(X > 525) = 1 - 0.7823\\\\P(X > 525) = 0.2177\\\\P(X > 525) = 21.77 \%

Therefore, there is 21.77% probability that a randomly selected teacher earns more than $525 a week.

How to use z-table?

Step 1:

In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 0.7, 2.2, 1.5 etc.)

Step 2:

Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 0.78 then go for 0.08 column)

Step 3:

Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.

3 0
3 years ago
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