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3 years ago

Please help me ASAP I’ll mark Brainly

Mathematics

1 answer:

Vesnalui [34]3 years ago

5 0

Answer:

117 sorry if I'm wrong ooh this agg

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Keegan says that a quadrilateral is a square if and only if it is a rectangle. Is this a true biconditional statement?

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No. It's not because quadrilaterals only have to have four sides for it to be considered one.

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4 years ago

What must be a factor of the polynomial function f(x) graft on the coordinate plane below

lilavasa [31]

Answer:

The correct answer option is B. (x - 1).

Step-by-step explanation:

We are to determine the factor of the polynomial function $f(x)$ which is graphed on the given coordinate plane.

We know that if the zeros (or intercepts) of an equation are $r _ 1$ and $r _ 2$ then the factors for this equation will be $( x - r _ 1 )$ and $( x - r _ 2 )$ .

From the graph, we can see that it intercepts the x axis at $1$ and $6$ . So the roots will be $(x-1)$ and $(x-6)$ .

Therefore, the correct answer option is B. (x - 1).

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4 years ago

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Use number properties to simplify the following expression. -4 + 6 + 4 In the box below, show each step in simplifying the expre

never [62]

Well, if you look at the expression -4+6+4, the -4 and the +4 cancel eachother out, totaling a 0, so NOW the expression is 0+6 which is obviously 6

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3 years ago

Read 2 more answers

The vertex of this parabola is at (-5, -2). When the x-value is -4, the y-value is 2. What is the coefficient of the squared exp

VARVARA [1.3K]

V(-5;-2)
$f(x)=a(x+5)^2-2$

$x=-4$ . $y=2$

$2=a(-4+5)^2-2$
$2=a*1-2$
$2=a-2$
$a=4$

The answer: B
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6 0

3 years ago

Find:

emmasim [6.3K]

Answer:

Step-by-step explanation:

Given the dataset 147, 154, 156, 161, 162,

Mean is the sum of the dataset divided by the total number of dataset.

a) Mean = $\sum Xi/N$

$\overline x = \dfrac{147+154+156+161+162}{5}\\ \\\overline x = \dfrac{780}{5}\\ \\\overline x= 156$

b) The formula for calculating the deviation from the mean for each value is expressed as $Xi - \overline X$ where;

Xi is value of each item

xbar is the mean = 156

Mean deviation of 147 = 147-156 = -9

Mean deviation of 154 = 154-156 = -2

Mean deviation of 156 = 156-156 = 0

Mean deviation of 161 = 161-156 = 5

Mean deviation of 162 = 162-156 = 6

c) Sum of the deviations $\sum Xi - \overline X$ = (-9-2+0+5+6)

$\sum Xi - \overline X$ = -11+11

$\sum Xi - \overline X$ = 0

Hence the sum of deviation from the mean is 0

5 0

3 years ago