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julia-pushkina [17]
2 years ago
8

Solve for y. xy + p = 5 A) y = 5 - p - x B) y = (5-p)/x C) y = 5 - px

Mathematics
1 answer:
Damm [24]2 years ago
6 0
Minus p both sides
xy=5-p
divide both sides by x
y=(5-p)/x

B
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This figure is made up of a quadrilateral and a semicircle.
Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of AB is

AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}

The length of AD is

AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}

Since AB=AD, therefore ABCD is a square. The area of the of square is

A_1=a\times a=\sqrt{29}\times \sqrt{29} =29

The area of square is 29 units².

The area of a semicircle is

A_2=\frac{\pi}{2}r^2

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

r=\frac{d}{2}=\frac{\sqrt{29}}{2}

The area of the semicircle is

A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825

The area of the figure is

A=A_1+A_2=29+11.2825=40.3825\approx 40.4

Therefore the area of the figure is 40.4 units². Option B is correct.

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3 years ago
Please help me with this problem ​
andreyandreev [35.5K]

Answer:

<em>1</em><em>.</em><em>p</em><em>r</em><em>i</em><em>c</em><em>e</em><em>(</em><em>dollars)</em><em> </em><em>and </em><em>soccer</em><em> </em><em>ball</em>

<em>2</em><em>.</em><em>y</em><em>=</em><em>3</em><em>0</em><em> </em><em>and </em><em>x=</em><em>5</em>

<em>3</em><em>.</em><em> </em><em>I </em><em> </em><em>think </em><em>5</em><em> </em><em>or </em><em>3</em><em>0</em>

Step-by-step explanation:

pa follow po

pa brainlest po

pa heart and 5 star

6 0
2 years ago
If PR = 5x – 3 and QS = 3x – 5 and QS == PR, what are the length of the<br> diagonals?
OleMash [197]

Answer:

Step-by-step explanation:

5x - 3 = 2(3x - 5)

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QS = 3(7) - 5 = 16 units

PR = 5 × 7 - 3 = 32 units

8 0
2 years ago
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