Help me please thank you

Valentina purchased al- yards of nylon as shown on the sales slip. Including tax, how much change should she get back?

mina [271]

Answer:

Step-by-step explanation:

Answer: D)$17.60

5 0

1 year ago

The top and bottom margins of a poster are each 15 cm and the side margins are each 10 cm. If the area of printed material on th

12345 [234]

Answer:

the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

Let p be the length of the of the printed material

Let q be the width of the of the printed material

Therefore pq = 2400 cm ²

q = $\dfrac{2400 \ cm^2}{p}$

To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be $\dfrac{2400 \ cm^2}{p} + 20$

The area of the printed material can now be: $A = (p+30)(\dfrac{2400 }{p} + 20)$

= $2400 +20 p +\dfrac{72000}{p}+600$

Let differentiate with respect to p; we have

$\dfrac{dA}{dp}= 20 - \dfrac{72000}{p^3}$

Also;

$\dfrac{d^2A}{dp^2}= \dfrac{144000}{p^3}$

For the smallest area $\dfrac{dA}{dp }=0$

$20 - \dfrac{72000}{p^2}=0$

$p^2 = \dfrac{72000}{20}$

p² = 3600

p =√3600

p = 60

Since p = 60 ; replace p = 60 in the expression q = $\dfrac{2400 \ cm^2}{p}$ to solve for q;

q = $\dfrac{2400 \ cm^2}{p}$

q = $\dfrac{2400 \ cm^2}{60}$

q = 40

Thus; the printed material has the length of 60 cm and the width of 40cm

the length of the poster = p+30 = 60 +30 = 90 cm

the width of the poster = $\dfrac{2400 \ cm^2}{p} + 20$ = $\dfrac{2400 \ cm^2}{60} + 20$ = 40 + 20 = 60

Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

4 0

3 years ago

A simple die is thrown 100 times and the number five appears 14 times. Find the experimental probability of throwing a five, giv

mario62 [17]

Answer:

The experimental probability of throwing a five is 0.087.

Step-by-step explanation:

Given:

Number of trials (n) = 100

Number of times 5 appears (x) = 14

Let the event of occurrence of 5 be success and the probability represented by 'p'. So, all the other numbers occurrence is failure and its probability is represented as 'q'.

Probability of success is given as:

$p=\frac{Number\ of\ favorable\ events}{Total\ number\ of\ outcomes}$

Favorable event is occurrence of 5. So, its number is 1 as there is only one 5 in the die. Total outcomes are 6 as there are six numbers. So,

$p=\frac{1}{6}$

Now, probability of failure is given by the formula:

$q=1-p=1-\frac{1}{6}=\frac{5}{6}$

Now in order to find the experimental probability of 14 successes out of 100 trials, we apply Bernoulli's theorem which is given as:

$P(x) = ^nC_xp^xq^{n-x}$

Plug in all the given values and find the probability of 14 successes. This gives,

$P(x=14)=^{100}C_{14}(\frac{1}{6})^{14}(\frac{5}{6})^{100-14}\\\\P(x=14)=0.087$

Therefore, the experimental probability of throwing a five is 0.087.

8 0

3 years ago

Multiple Representations:Question 1

alexdok [17]

Answer:

y = 27.1

Step-by-step explanation:

We have the value of x:

x = 12

and we need to find the value of y in the expression:

y = x + 15.1

as we can see by the equation, the value of y depends on the value of x.

thus, we substitute x = 12 on the previous equation:

y = 12 + 15.1

y = 27.1

the value of y is 27.1

7 0

3 years ago

Help please, I need to figure this problem out

yarga [219]

Answer:

AB is parallel to BE because it is an equilateral triangle.

BE is parallel to EC because it has 2 of the same angles to the same sides are equal.

Hope that helps, it's a tad hard to explain

7 0

3 years ago