Part A
The given line passes through (-2,2) and it is parallel to the line

We need to determine the slope of this line by writing it in slope -intercept form.


The slope of this line is

The line parallel to this line also has slope

The equation is

We substitute (-2,2)


The required equation is

PART B
The given line is

The slope of this line is

The slope of the line perpendicular to it is

The equation of the line is

We substitute the point, (-2,2)



The equation of the perpendicular line is
Answer:
y = 3/4 x - 5
Step-by-step explanation:
The slopes of perpendicular lines are negative reciprocals. We find the slope of the given line. Then we can find the slope of the reciprocal.
4x + 3y = -6
Solve for y.
3y = -4x - 6
y = -4/3 x - 2
The slope of the original line is -4/3.
The slope of the perpendicular is 3/4.
Now we need to find the equation of line with slope 3/4 that contains point (4, -2).
y = mx + b
-2 = (3/4)(4) + b
-2 = 3 + b
-5 = b
b = -5
The equation is
y = 3/4 x - 5
Answer:
m/3
Step-by-step explanation:
13 m or m 3
Explanation:One third = 13 (the number)'Of' = multiplication (symbol : ×)
a number m = m (variable)
One third of a number m= (one third)(a number m)= (13)(a variable) = (13)
(m)= 13 m or m 3 since 13 m = m/3
Scale factor is 3. Multiply the small sides by 3