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3 years ago

A Web site defines a regular polygon as “a polygon with all angles the same measure.” Is this definition valid?

Mathematics

2 answers:

aniked [119]3 years ago

8 0

Answer:

Option D is correct .

Step-by-step explanation:

A polygon is a two-dimensional figure made up of straight lines.

A polygon is said to be regular if all its angles are equal.

For example:

equilateral triangle, square, pentagon, hexagon, heptagon, octagon, decagon are all regular polygons as they all have equal angles .

A Web site defines a regular polygon as “a polygon with all angles the same measure.” We need to find if this definition valid?

Given Options:

A. No, because not all regular polygons fit this definition.

B. No, because some polygons that are irregular fit this definition.

C. Yes, because a square is a regular polygon.

D. Yes, because all regular polygons fit this definition.

Option D is correct .

grandymaker [24]3 years ago

3 0

Answer:

Yes, because all regular polygons fit this definition.

Choice D is correct

Step-by-step explanation:

A polygon is said to be regular if it is equiangular that is all its angles are equal and equilateral which implies that all its sides have equal length. Examples of regular polygons include;

Regular pentagon

Regular octagon

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A blue marlin can swim at speeds of about 50 miles per hour what is that speed in feet per second to the nearest whole number (r

sleet_krkn [62]

Multiply the amount of feet in one mile by the amount of miles in the question(5,280 x 50 = 264,000)

Divide the amount of feet in 50 miles by the amount of minutes in 1 hour to get the amount of feet per mile (264,000 ÷ 60 = 4,400)

Divide the amount of feet per mile to get by the amount of seconds in a minute to get the amount of feet per second (4,400 ÷ 60 = 73.33)

Your answer rounded to the nearest whole number is "73"

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3 years ago

Graphing<br>solve a system of equation by graphing

Alex787 [66]

SOLUTION:

$Point \ (1,3)$

<h2>Explanation:</h2>

Let's use the following System of Linear Equations in Two Variables in order to solve this exercise:

$\begin{array}{c}(1)\\(2)\end{array}\left\{ \begin{array}{c}y=2x+1\\y=-4x+7\end{array}\right.$

So we can graph these lines using two points.

For eq (1):

$y=2x+1 \\ \\ If \ x=0 \ then \ y=2(0)+1 \therefore y=1 \\ \\ If \ y=0 \ then \ 0=2x+1 \therefore x=-\frac{1}{2} \\ \\ \\ Points: \\ \\ (0,1) \\ \\ (-\frac{1}{2},0)$

So graph a line that passes through these two points. This is the red line shown below.

For eq (2):

$y=-4x+7 \\ \\ If \ x=0 \ then \ y=-4(0)+7 \therefore y=7 \\ \\ If \ y=0 \ then \ 0=-4x+7 \therefore x=\frac{7}{4} \\ \\ \\ Points: \\ \\ (0,7) \\ \\ (\frac{7}{4},0)$