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3 years ago

A standard fair dice is rolled twice.

Mathematics

2 answers:

eimsori [14]3 years ago

7 0

Answer:

5/12

Step-by-step explanation:

<em>Probability = favorable outcomes / total outcomes</em>

P(odd) = 3/6 = 1/2 (there are 3 odd numbers out of 6 on a dice)
P(no 1) = 5/6
P(odd and no 1) = 1/2*5/6 = 5/12

ExtremeBDS [4]3 years ago

7 0

Answer:

5/12

Step-by-step explanation:

Hope this helps

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You mean, what is this number?

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x+8=15

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A bag contains 5 red marbles, 7 blue marbles and 4 green marbles if two marbles are drawn out of the bag what is the probability

Ann [662]

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3 years ago

Calculate the average (arithmetic mean) of the list of numbers shown in the table. (rounded to the nearest tenth) A) 35.2 B) 39.

jenyasd209 [6]

<h3><u>Given Numbers:-</u></h3>

23, 33 ,33 ,27 ,25 ,68 ,27 ,44 ,72

average of this set of numbers

<h3><u>Solution</u>:-</h3>

$\green{ \underline { \boxed{ \sf{Average = \frac{Sum \:of \: observation}{Number \:of \: observation}}}}}$

$\longrightarrow$ Here, no of observation are 9

Now,

$\begin{gathered}\implies \small \sf Average =\frac{23+33+33+27+25+68+27+44+72}{9}\\\end{gathered}$

$\begin{gathered}\\\implies \small \sf Average =\frac{56+60+93+71+72}{9}\\\end{gathered}$

$\begin{gathered}\\\implies \sf Average =\frac{116+164+72}{9}\\\end{gathered}$

$\begin{gathered}\\\implies \sf Average =\frac{352}{9}\\\end{gathered}$

$\begin{gathered}\\\implies \sf Average = 39.1 \\\end{gathered}$

$\longrightarrow$ The Average of given set of numbers is 39.1 .

∴ Option C) is correct ✔️

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