The equation for the circle below is x^2+y^2=4. what is the length of the circle’s radius

1 answer:

6 0

2 because in the equation of a circle it is x^2 + y^2 = r^2, r=radius so you would take the square root of 4, leaving the radius of the circle to be 2.

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Identify the domain and the range.

QveST [7]

Domain -x axis
Range-Y axis

7 0

4 years ago

Solve pls i need answer asap<br> all 1-6

sergiy2304 [10]

Step-by-step explanation:

the domain is the set or interval of all valid x values.

the range is the set or interval of all valid y values.

domain = {-1, 2, 5}

range = {0, 2, 3, 7}

function : no, because x = -1 has 2 different y values assigned (7 and 2). that violates the definition of a function.

domain = {-3, -2, -1, 1, 4}

range = {-5, -1, 0, 2}

function : yes. every x bake has exactly one y value assigned.

domain = {4, 6, 7}

range = {-1, 2, 3, 5}

function : no, because x = 4 has 2 different y values assigned (2 and 5).

domain = [-3, 3) "3" is not included, hence the empty dot

range = [-4, 5]

function : yes

domain = (-infinity, +infinity) "infinity" is not a possible value, so the limits are not included.

range = [-1, 2]

function : yes

domain = [-2, +infinity)

range = (-infinity, +infinity)

function : no. except for x = -2 all x values have 2 different y values assigned.

3 0

2 years ago

una familia ha consumido en un dia de verano: dos botellas de litro y medio de agua, 5 botellas de 1/4 de litro de jjugo de appl

aleksandr82 [10.1K]

Answer:

La familia ha bebido en un día de verano $5\,\frac{1}{4}$ litros.

Step-by-step explanation:

Podemos evidenciar que es posible obtener el volumen total de los citados líquidos al sumar el volumen de cada uno. El volumen de cada bebida es igual al producto de su capacidad multiplicada por el número de botellas. Es decir:

$V_{total} = V_{agua} + V_{jugo} + V_{limonada}$

Donde todos los volúmenes se miden en litros.

$V_{total} = (2\,botellas)\times \left(\frac{3}{2} \,\frac{L}{botella} \right)+(5\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right) + (4\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right)$

$V_{total} = (2\,botellas)\times \left(\frac{6}{4} \,\frac{L}{botella} \right)+(5\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right) + (4\,botellas)\times \left(\frac{1}{4}\,\frac{L}{botella} \right)$