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Zigmanuir [339]
3 years ago
5

Simplify (-3xy2z2) (-2x4y3z)3

Mathematics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

the answer is

18x^5y^5z^3

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-3/10 + 4/15<br> Solve the above problem
Firlakuza [10]

Answer:

-1/30

Step-by-step explanation:

find the lcm of 10 and 15

then solve it

3 0
2 years ago
The sum of Alex's height and Ben's height is 130 inches. Subtracting Alex's height from Ben's height yields one-third of Ben's h
In-s [12.5K]

Ben is 97.5 inches tall.

Alex is 32.5 inches tall.

5 0
3 years ago
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What is 2/3x=10 one step equations
stellarik [79]
Multiply both sides by three to get 2x=30
Then divide both sides by 2 to get x=15
7 0
3 years ago
Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ
-Dominant- [34]

Answer:

\tan(\beta)

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)

\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }

\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}

\sin(\beta) *\dfrac{1 }{\cos(\beta) }

\dfrac{\sin(\beta)}{\cos(\beta) }

Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

8 0
2 years ago
What is 0.77 estimated
galina1969 [7]
The answer would be .80 or it may be 1
5 0
2 years ago
Read 2 more answers
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