Answer:
C. 2x^4; E. -5x
Step-by-step explanation:
P(x) = x^3 − x − 2 and Q(x) = x^2 + 2x + 1
P(x) * Q(x) = (x^3 − x − 2)(x^2 + 2x + 1) =
= x^5 + 2x^4 + x^3 - x^3 - 2x^2 - x - 2x^2 - 4x - 2
= x^5 + 2x^4 - 4x^2 - 5x - 2
Answer: C. 2x^4; E. -5x
Answer:
81 F
Step-by-step explanation:
Hours | Temp.
0 | 75F
1 | 77F
2 | 79F
3 | 81F
I have encountered this question before. Since only the product of the ages is given, there are a lot of possible combinations.
3 kids, has a youngest child - means that the 3 kids have different ages.
I performed a prime factorization on 72.
72 ÷ 2 = 36
36 ÷ 2 = 18
18 ÷ 2 = 9
9 ÷ 3 = 3
3 ÷ 3 = 1
1 x 2 x 2 x 2 x 3 x 3 = 72
Possible age combination:
1 x 8 x 9 = 72
2 x 4 x 9 = 72
3 x 4 x 6 = 72
1 x 6 x 12 = 72
1 x 4 x 18 = 72
Just substitute in the numbers:
7j+5-8k
=7(0.5) + 5 - 8(0.25)
=3.5 + 5 - 2
=6.5
Rectangles are similar figures, thus if scaled copies of each other then the ratios of corresponding sides must be equal
compare ratios of lengths and widths
rectangles A and B
k = 
= 
← ratio of lengths
k = 
= ← ratio of widths
scale factors are equivalent, hence rectangle A is a scaled copy of B
rectangles C and B
k = 
= 
← ratio of lengths
k = 
= 
← ratio of width
scale factors (k ) are not equal, hence C is not a scaled copy of B
rectangles A and C
k = 
= 
← ratio of lengths
k = 
← ratio of widths
the scale factors are not equal hence A is not a scaled copy of C
