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Liula [17]
3 years ago
15

10 to the tenth power​

Mathematics
1 answer:
Gala2k [10]3 years ago
7 0

over 9000 becuz it is over 9000

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If the interior angle of a polygon is 170 how many sides does it have
Tpy6a [65]

if interior angle is 170, subtract 170 from 180 to find exterior angle:

180-170 = 10 = exterior angle

the sum of exterior angles is 360 so divide by exterior angle to find sides:

360 /10 = 36 sides

6 0
3 years ago
Quadrilateral OPQR is inscribed in circle N, as shown below. What is the measure of ∠PQR? (5 points)
dimulka [17.4K]

Answer:

is there a picture?

Step-by-step explanation:

7 0
3 years ago
700​% of what number is 4,340​?
Luden [163]

Answer:

620

Step-by-step explanation:

100% must be the the answer so 700% must be 7 times that number.

4340÷7=620

7 0
2 years ago
Read 2 more answers
Which expression has a value of -2? *<br> O 1-4+121<br> O 121 +1-41<br> O 141-121<br> O 1-21-1-41
irga5000 [103]

Answer:

None.

Step-by-step explanation:

1 - 4 + 121

= -3 + 121

= 118

121 + 1 - 41

= 122 - 41

= 81

141 - 121

= 20

1 - 21 - 1 - 41

= -20 - 1 - 41

= -21 - 41

= -62

None of the expressions have a value of -2.

6 0
3 years ago
Can I please have help with question 2) a and b
Ulleksa [173]

Answer:

\frac{10\sqrt{6} }{3} and \frac{11\sqrt{3} }{3}

Step-by-step explanation:

(a)

A = \frac{1}{2} × 4\sqrt{2} × \frac{5}{\sqrt{3} }

   = 2\sqrt{2} × \frac{5}{\sqrt{3} }

   = \frac{10\sqrt{2} }{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } ← rationalise the denominator

= \frac{10\sqrt{6} }{3} units²

(b)

Using Pythagoras' identity in the right triangle

let hypotenuse be h , then

h² = (4\sqrt{2} )² + (\frac{5}{\sqrt{3} } )²

    = 32 + \frac{25}{3}

    = \frac{96}{3} + \frac{25}{3}

    = \frac{121}{3} ( take the square root of both sides )

h = \sqrt{\frac{121}{3} } = \frac{11}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } ← rationalise the denominator

h = \frac{11\sqrt{3} }{3}

 

7 0
3 years ago
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