1 over 4a = 2 over 3. Which of the following equals a in this equation?

Given isosceles triangle HGI, With legs HI and GI and median IJ, find measure of angle HIJ.

Verdich [7]

That’s hard umm idk look it up and it will tell you

6 0

3 years ago

1. An LG Dishwasher, which costs $800, has a 20% chance of needing to be replaced in the first 2 years of purchase. A two-year e

yKpoI14uk [10]

Step-by-step explanation:

The expected value of the extended warrant is calculated as follow.

Value of Waranty

= 800 x 20% − 112.10

= 800 x 20/100 − 112.10

= 47.9

The expected value of the extended warranty assuming it is replaced in the first 2 years is given as follow.

Expected value=800-112.10=>687.90

Therefore, required expected value of extended warranty is 687.90

2.

Given information:

Number of Trials (n) = 15

Probability of Success (p) = 0.10

a) Let X represents the number of left-handed people.

b) The probability distribution follows binomial distribution.

X ∼ Binomial distribution

The probability distribution is given as follow.

P(X = x) = ^nCx(p)^x(1 − p)^n − x

c)The histogram is given as follow. (See attachment)

d) The shape of histogram is skewed right.

e) The mean is calculated as follow.

Mean

=n x p

= 15 x 0.10

= 1.5

f) The variance is calculated as follow.

Variance

= n x p x q

= 15 x 0.10 x 0.90

= 1.35

g) The standard deviation is calculated as follow.

Standard deviation

=√n x p x q

=√15 x 0.10 x 0.90

= 1.162

8 0

3 years ago

The function f(x)=(x-5)^2 +2 is not one-to-one. Identify a restricted domain that makes the function one-to-one, and find the in

Anon25 [30]

We have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

We know that vertex of this quadratic function occurs at (5,2).

Further, we know that range of this function is $[2,\infty)$ .

If we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

Let us know find its inverse.

$y=(x-5)^{2}+2$

Upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

Let us now solve this function for y.

$(y-5)^{2}=x-2\\
y-5=\pm \sqrt{x-2}\\
y=5\pm \sqrt{x-2}\\$

Hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

8 0

3 years ago

At a bargain store.Tanya bought 5 items that each cost the same amount. Tony bought 6 items that each cost the same amount, but

Ray Of Light [21]

(A) For x representing the cost of one of Tanya's items, her total purchase cost 5x. The cost of one of Tony's items is then (x-1.75) and the total of Tony's purchase is 6(x-1.75). The problem statement tells us these are equal values. Your equation is ...

... 5x = 6(x -1.75)

(B) Subtract 5x, simplify and add the opposite of the constant.

... 5x -5x = 6x -6·1.75 -5x

... 0 = x -10.50

... 10.50 = x

(C) 5x = 5·10.50 = 52.50

... 6(x -1.75) = 6·8.75 = 52.50 . . . . . the two purchases are the same value

(D) The individual cost of Tanya's iterms was $10.50. The individual cost of Tony's items was $8.75.

6 0

3 years ago

Is there a mistake in this equation? if not please let me know!

Juli2301 [7.4K]

Answer:

no mistakes

Step-by-step explanation:

4 * 3^x = 324

Divide each side by 4

4/4 * 3^x = 324/4

3^x = 81

Rewriting 81 as a power of 3

3^x = 3^4

Since the bases are the same, the powers are the same

x=4

5 0

3 years ago

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