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kirza4 [7]
4 years ago
12

P

Mathematics
1 answer:
olga55 [171]4 years ago
6 0

Answer:

453o

Step-by-step explanation:

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What is 1/2 times 700
Fiesta28 [93]

Answer:

350

Step-by-step explanation:

3 0
3 years ago
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8 1/2 + 2 7/9 = ----- fill in the lkank
Alex

Answer:

The answer is 11 5/18 because it is so easy.

3 0
3 years ago
Baxter is thinking about buying a car. The table below shows the projected value of two different cars for three years.
MAVERICK [17]

Answer:

A) car 1: exponential

   car 2: linear

B) car 1: f(x)=18500(0.94)^{x-1}

    car 2: f(x)=-1000x+19500

C) Yes, there will be a significant difference of $1,100.40 which is approx 10% of the value of the cars after 10 years.

Step-by-step explanation:

<u>Part A</u>

Car 1: exponential as the projected value is not decreasing by the same amount each year

Car 2: linear as the projected value decreases by the same amount each year ($1000)

<u>Part B</u>

<u>Car 1</u>

General form of exponential function: y=ab^x

a = initial value = 18500

b = growth factor = \dfrac{17390}{18500}=0.94

\implies f(x)=18500(0.94)^{x-1}

NB We have to change x to "x-1" since we are told in the table that <u>after</u> 1 year the car's value is 18500.

<u>Car 2</u>

General form of linear function:  y=mx+b

m=\dfrac{\textsf{change in} \ y}{\textsf{change in} \ x}=\dfrac{17500-18500}{2-1}=-1000

y-y_1=m(x-x_1)

\implies y-17500=-1000(x-2)

\implies f(x)=-1000x+19500

<u>Part C</u>

Car 1 after 10 years: \implies f(10)=18500(0.94)^{10-1}=\$10,600.40

Car 2 after 10 years: \implies f(10)=-1000(10)+19500=\$9,500

Difference = 10600.40 - 9500 = 1100.40

Yes, there will be a significant difference of $1,100.40 which is approx 10% of the value of the cars after 10 years.

6 0
2 years ago
I really need help!!!!!!!!!!!!
Debora [2.8K]
I am not 100% positive but from what I remember learning I think the answer you are looking for on the first question is C.
6 0
3 years ago
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How would i write 36-4×f if my only options were 36-f or 36(4f)
laila [671]
You would write 36- (4f).

hope this helps you
7 0
4 years ago
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