Choose from the following list the three genotypes the parents must have in order for a daughter to have XbXb . XBXB XBXb XY XbX
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Answer: The genotype ratio is 2Ff : 2ff
The phenotype ratio is two normal feathered birds to two silky feathered birds.
Explanation: Let F represent the gene for normal feather and f represent the gene for silky feather. F is dominant while f is recessive, therefore a male that is hybrid for trait of normal feather is heterozygous and will have a genotype of Ff, a female that is homozygous for silky feather will have a genotype of ff.
A cross between Ff and ff will yield 2Ff birds and 2ff birds. Since F is dominant, a bird having genotype of Ff will manifest outwardly as blue feathered birds while ff will manifest outwardly as silky feathered birds because f is recessive and must occur in a homozygous condition in order to manifest phenotypically. Therefore, the genotype ratio is 2Ff: 2ff.
See the punnett square attached for more information
